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oksian1 [2.3K]
3 years ago
13

The weight of a sack of potatoes was more than 11 pounds. Shana wants to write an inequality for the weight of the sack of potat

oes. What constant should she use in the inequality?
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
6 0
P > 11.....ur constant is 11
myrzilka [38]3 years ago
5 0

Answer:  The constant that Shana should use in the inequality is 11.

Step-by-step explanation:  Given that the weight of a sack of potatoes was more than 11 pounds and she wants to write an inequality for the weight of the sack of potatoes.

We are to find the constant that she should use in the inequality.

Let x pounds represents the weight of the sack of potatoes.

Then, according to the given information, the inequality can be written as

x>11.

Thus, the required constant that Shana should use in the inequality is 11.

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Which expression lists the three consecutive integers starting with a number x? A. x, x + 2, x + 4 B. x + 1, x, x + 2 C. x – 1,
Vika [28.1K]

Consecutive integers are like 1, 2, and 3. They are in a row. Think about plugging numbers in for x. 1 and 1+2 are not consecutive, so A is not the answer. B and C don't start with x, so they aren't the answer. That leaves D, because it starts with x, then goes to x+1, and then to x+2. These are consecutive, because if x was 1, it would be 1, 2, 3.

The answer is D.

I hope this helps :)

3 0
3 years ago
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Scilla [17]

Answer:

\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi

Step-by-step explanation:

Area of a circle with radius r: r^2\pi

Circumference of a sector with radius r: 2r\pi

Area of sector with angle \theta:  r^2\pi\cdot \frac{\theta}{360}.

Arc length of sector with angle \theta: 2r\pi\cdot \frac{\theta}{360}

Using these equations, we get the following information:

Area of circle: 27^2\pi=729\pi

Circumference of a circle: 2\cdot 27\cdot \pi=54\pi

Area of sector: 27^2\pi\cdot \frac{80}{360}=162\pi

Arc length of sector: 2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi

3 0
2 years ago
the length of a new rectangle playing field is 6 yards longer than quadruple the width. if the perimeter of the rectangle plaing
Vika [28.1K]

The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

The length of a new rectangle playing field is 6 yards longer than quadruple the width.

Let's suppose the length is l and width is w of a rectangle:

From the problem:

l = 6 + 4w

Perimeter P = 2(l + w)

532 = 2(l + w)

Plug l = 6+4w in the above equation:

532 = 2(6 + 4w + w)

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260 = 5w

w = 52 yards

l = 6 +4(52) = 214 yards

Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

Learn more about the area of rectangle here:

brainly.com/question/15019502

#SPJ1

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Answer:

1

Step-by-step explanation:

\frac{1}{4}  \times 4 = 1

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