Answer:
Y=4
Step-by-step explanation:Solve for yy in (y=4)(y=4).
y=4y=4
2 Substitute y=4y=4 into 1-1/2=2
2
No Solution
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work
EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same
For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y
For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4
Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.
Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the
x²y = -4 ... (I)
Condition 2: Real parts are the same
x² + y = -3 ... (II)
We have a system of equations since both conditions must be satisfied
x²y = -4 ... (I)
x² + y = -3 ... (II)
We can rearrange equation (II) so that we have
y = -3 - x² ... (II)
Substituting into equation (I)
x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0
Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.
Solve for y:
y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4
So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:
-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i
x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i
They result in conjugates
Answer:
Option C, both functions have an y-intersect equal to 2.
Step-by-step explanation:
When we have a function f(x), the y-intercept is the value f(0). This is the point where the graph of the function intersects the y-axis.
Then, for f(x) = -x^2 + 5*x + 2
The y-intercept is:
f(0) = -0^2 + 5*0 + 2 = 2
f(0) = 2
And for g(x) we do not have the equation, but we have the graph, so we can just look at which value of y does the graph intersects the y-axis.
We can see that the graph intersects the graph at y = 2
Then the y-intersect is: g(0) = 2
So both functions have the same y-intersect. Then the correct option is C.
The ball is at a height of 14 feet after 1.17 and 0.64 seconds.
This is an example of a quadratic equation. Write out the equation with 14 in the place of the height. Then, set it equal to zero.
14 = 2 + 29t - 16t^2
0 = -16t^2 + 29t -12
Now, we can use the quadratic equation to solve.
A = -16
B = 29
C = -12
You will get the solutions of 1.17 and 0.64.
Answer: 2/1
Step-by-step explanation:
2/1 because you use rise/run which is moving up 2 units from (0,3) to (0,5) and then moving right 1 unit to (1,5)
