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snow_lady [41]
3 years ago
14

Describe the process of a bactirium cell

Biology
1 answer:
Strike441 [17]3 years ago
6 0

Answer:

Bacteria reproduce by binary fission. In this process the bacterium, which is a single cell, divides into two identical daughter cells. Binary fission begins when the DNA of the bacterium divides into two (replicates).

Explanation:

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At the end of meiosis ll, each of the haploid sex cells had only half the number of chromosomes as the original diploid cell. Wh
tester [92]

Answer:

The cells at the end of meiosis II must have half the number of chromosomes because, if they didn't have, the reunion of both gametes with diploid number of chromosomes for example, in gametes would form twice the number chromosomes.

5 0
2 years ago
What energy transformation occurs during photosynthesis?
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<u>Light Energy to Chemical Energy</u> is the transformation that occurs during photo synthesis.

<em><u>I hope this helps!</u></em>

8 0
3 years ago
Cerumen is produced by glands located in the
borishaifa [10]
Stratum corneum is the answer
4 0
3 years ago
Desalination is needed in order to obtain potable water from _____.
Vinvika [58]
Answer:  [D]:  "oceans" .
_______________________________________
Note:  Among the answer choices given—{aquifers, glaciers, lakes, oceans}—oceans are the saltiest (VERY salty—requiring "desalination" in order to obtain potable water.
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4 0
3 years ago
Read 2 more answers
Sickle cell anaemia is an inherited autosomal recessive
alekssr [168]

Answer:

1/8 (12.5%)

Explanation:

An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).

- Parental cross for sickle cell anaemia trait = Hh x Hh >>

- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>  

- Sex proportion of sickle cell anaemia individuals =  1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)

3 0
2 years ago
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