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choli [55]
4 years ago
8

How can I solve this system of linear equation by substitution 3x+y=11 and -2x+y=1

Mathematics
2 answers:
Alecsey [184]4 years ago
8 0
First will make Equation take on the form of y = mx + b. I've cchosen the second Equation:

y = 2x + 1


Now substitute this equation in for y into the other equation and solve:

<span>3x+y = 11
</span><span>3x+ (2x + 1)=11
5x + 1 = 11
</span><span>5x = 11 - 1
</span><span>5x/5= 10/5
x = 2 


You can now plug this x-value back into </span><span>either equation, and solve for </span>y:
<span>
y = 2(x) + 1
</span>y = 2(2) <span>+ 1</span>
y = 5

erastovalidia [21]4 years ago
6 0
We can answer this question by solving each equation for one variable, and then substituting.

3x + y = 11   Given
y = -3x + 11   Subtract 3x from both sides

This equation is now solved for y. Now, let's do the other equation. Make sure to solve it for the same variable.

-2x + y = 1   Given
y = 2x + 1   Add 2x to both sides

Now, let's set both equations equal to each other, since they both equal y.

2x + 1 = -3x + 11   Set both equations equal to each other
1 = -5x + 11   Subtract 2x from both sides
-10 = -5x   Subtract 11 from both sides
2 = x   Divide both sides by -5

Now, let's substitute x in for one of the equations we found earlier, so that we can find y.

y = 2x + 1   Given
y = (2)(2) + 1   Substitute the x-value, 2
y = 4 + 1   Multiply
y = 5   Add

So, x = 2 and y = 5.

Hope this helps!


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Write a linear equation in point slope form that passes through the point (-2,5) with a slope or 1/2
trasher [3.6K]

Answer:

y-5=\frac{1}{2}(x+2)

Step-by-step explanation:

Point Slope is:

y-y_1=m(x-x_1)

We are given the point (-2, 5) and a slope of 1/2.

y-y_1=m(x-x_1)\rightarrow\boxed{y-5=\frac{1}{2}(x+2)}

Hope this helps.

4 0
3 years ago
Tony is laying out the design for a concrete path.
Anastaziya [24]

Answer:

Area of shape = 10.8 m²

Step-by-step explanation:

Given:

Length of rectangle 1 = 4000 mm = 4 m

Width of rectangle 1 = 1200 mm = 1.2 m

Length of rectangle 2 = [6200-1200] mm = 5 m

Width of rectangle 2 = 1200 mm = 1.2 m

Find:

Area of shape

Computation:

Area of shape = Area of rectangle 1 + Area of rectangle 2

Area of shape = [(4)(1.2)] + [(5)(1.2)]

Area of shape = 4.8 + 6

Area of shape = 10.8 m²

4 0
3 years ago
?????????help??????????
maxonik [38]
I hope it will work
6 = (0.08)w
6 0
3 years ago
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7 0
3 years ago
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What is the solution set of x^2+y^2=26 and x-y=6
Strike441 [17]
x^{2} + y^{2} =26  x-y=6  x=y+6&#10; Replacing in equation;  (y+6[tex] )^{2}+y^{2}=26
y^{2} +12x+36+ y^{2} =36
=2y^{2} +12x+36-26=0
=2y^{2} +12x+10=0
Product = 12
Sum= 10
factoring;
2y^{2}+2y+10y+10=0
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1

4 0
4 years ago
Read 2 more answers
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