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3 years ago

What is the value of |C| in this matrix

Mathematics

1 answer:

damaskus [11]3 years ago

6 0

Answer:

-12

Step-by-step explanation:

required value is det(C)

detC = (-6×4)-(6×-2)

so |C| = -24+12

=-12

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Find the measure of the sides of angle ABC with vertices A(1,5), B(3,-2), and C(-3,0). Classify the triangle

Charra [1.4K]

Answer:

$AB=\sqrt{53},\ BC=\sqrt{40},\ CA=\sqrt{41}\\It\ is\ an\ acute\ triangle$

Step-by-step explanation:

The distance between two points $(x_1,y_1),\ (x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

Here $A(1,5),\ B(3,-2),\ C(-3,0)$ are the vertices of a triangle.

$AB=\sqrt{(-2-5)^2+(3-1)^2}=\sqrt{(-7)^2+(2)^2}=\sqrt{49+4}=\sqrt{53}=7.28\ unit\\\\BC=\sqrt{(0+2)^2+(-3-3)^2}=\sqrt{(2)^2+(-6)^2}=\sqrt{4+36}=\sqrt{40}=6.32\ unit\\\\CA=\sqrt{(5-0)^2+(1+3)^2}=\sqrt{(5)^2+(4)^2}=\sqrt{25+16}=\sqrt{41}=6.40\ unit$

Longest side $=AB$

$AB^2=53\\BC^2+CA^2=40+41=81\\\Rightarrow AB^2$

Hence this is an acute triangle.

6 0

3 years ago

BRAINLIEST, THANK AND 5 STARS FOR RIGHT ANSWER!!!!

Strike441 [17]

Answer:

Step-by-step explanation:

$$ You did not state whether this is simple or compound interest.$ \\ \\ $Simple$ \\ \\ A=Prt\\ \\ t= \frac{A}{Pr}\\ \\ t= \frac{10100}{4400(.07)}\approx 33 \\ \\ $ Compound $ \\ \\ A=P(1+r)^t\\ \\ t=ln\frac{A}{P}/ln(1+r)\\ \\ t=ln\frac{10100}{4400}/ln(1.07)\\ \\ t\approx 12$

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3 years ago

X/4 < -1.5 for a million dollars and Brainliest. Send cash app too

pogonyaev

Answer:

x < -6

Step-by-step explanation:

X/4 < -1.5

Multiply each side by 4

X/4*4 < -1.5*4

x < -6

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3 years ago

What is the median of 60 57 53 78 44 51 please help and thank u

maksim [4K]

To find the median cancel out numbers on both sides, until one is left in the middle and if there are two in the middle add them up and divide by two.

So in this case the median is
53+78
131 / 2
65.5

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Triangles F H G and K J G share common point G. The lengths of sides H G and G J are congruent. Angles F H G and K J G are right

Elza [17]

The answer is D...........

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3 years ago

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