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34kurt
3 years ago
13

Lines c and d are perpendicular. if the slope of line c is -4, what is the slope of line d?

Mathematics
1 answer:
torisob [31]3 years ago
8 0
The slope of line d is 1/4.
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Solve the following system of equations using elimination: <br> -x+5y=8 <br> And<br> 3x+7y=-2
djyliett [7]

Answer:

x=-3, y=1. (-3, 1).

Step-by-step explanation:

-x+5y=8

3x+7y=-2

----------------

3(-x+5y)=3(8)

3x+7y=-2

--------------------

-3x+15y=24

3x+7y=-2

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22y=22

y=22/22

y=1

-x+5(1)=8

-x+5=8

-x=8-5

-x=3

x=-3

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2 years ago
David invested $220 in a savings account that offers a 3% return on the investment. The value of David's investment will be at l
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400=220(1.03)^t
1.8181=1.03^t
ln 1.8181=ln 1.03^t=t ln 1.03
ln 1.8181/ln 1.03=t
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8 0
3 years ago
A wire stretches from the top of a pole 8m high to a stake in the ground which is 6m from the foot of the pole. Find the length
kap26 [50]
It is 48 m high. I got no help (by the way)
4 0
3 years ago
I think I wrote question wrong, it’s what is the biggest even number I can make using all four numbers 4,6,3,1 I don’t think it’
Lera25 [3.4K]

Answer:

4 digits even number - 6314

8 0
3 years ago
Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 51% chan
Charra [1.4K]

Answer:

a) 0.3270 = 32.70% probability that Christine fails the course

b) 0.3917 = 39.17% probability that she had found someone to help

Step-by-step explanation:

We have these following probabilities:

61% probability that Christine find a coach.

100 - 61 = 39% probability that Christine does not find a coach.

With a coach, a 21% probability of failing.

Without a coach, a 51% probability of failing.

a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

P = 0.21*0.61 + 0.51*0.39 = 0.327.

0.327 = 32.7% probability that Christine fails the course

b. Christine ends up failing the course. What is the probability that she had found someone to help?

This can be formulated by the Bayes formula:

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

P(A) is the probability of failing. So P(A) = 0.327.

So

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917

0.3917 = 39.17% probability that she had found someone to help

4 0
3 years ago
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