Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
No because when you do 3*--9 = 27 and 4*--12 =48
Answer:
C hdgkddjgxjvvnCbbcBcgsjgzjvzjvhfhfh
Answer:
<h2>infinitely many solutions</h2>
Step-by-step explanation:
5x - 6 = 3x - 6 + 2x <em>combine like terms</em>
5x - 6 = (3x + 2x) - 6
5x - 6 = 5x - 6 <em>subtract 5x from both sides</em>
-6 = -6 TRUE
Therefore the equation has infinitely many solutions.
X^2+20x+10 that's the answer
