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raketka [301]
3 years ago
8

In a board game, players lose 50 points every time they land on a red space. If there is no other way to lose points and Jamie h

as a score of -450 points, what is the minimum number of times he could have landed on a red space?
Mathematics
1 answer:
Simora [160]3 years ago
7 0
Since players are losing points every time they land on a red space, it is -50,
Here's our equation where c equals the amount of times.
-50C=-450
We need C by itself, we need to divide.
-450÷-50=9
Since there is no other way to lose points, we don't have to worry about the slope in this equation. But, there might be a way to gain points. We have it set at 0 assuming that Jamie did not score any points. This allows us to get the minimum times her could have landed.
The minimum number of times he could have landed on a red space is 9 times.
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3 years ago
A pet toy manufacturer is designing a plastic ball for dogs that will float in water. In order for the ball to float it must hav
algol13

Answer:

3.576 cm

Step-by-step explanation:

radius of ball, r=?

Given:

Density, p = 0.600g/mL

mass, m= 115g

finding volume, v of ball by using formula p=m/v

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If line segment BH = 3, line segment BF = 10, line segment GH= 2, find HD 15 11 10.5 ?
pav-90 [236]

HD = 10.5

Step-by-step explanation:

Given BH = 3, GH = 2, BF = 10

Step 1: To find HF:

HF = BF – BH

HF = 10 – 3

HF = 7

Step 2: To find HD:

We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.

⇒ GH × HD = BH × HF

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⇒ HD = 10.5

Hence, the value of HD = 10.5.

5 0
3 years ago
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Answer:

900 divided by 30.48 =

Step-by-step explanation:

<u> 0 0. 0 3 3</u>

9 0 0 3 0. 4 8 0

   − 0        

     3 0      

<u>    −   0   </u>  

     3 0 4    

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