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3 years ago

How do you find the hypotenuse of a triangle with only one side?

Mathematics

1 answer:

weeeeeb [17]3 years ago

8 0

What ever number is on the largest side

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Find the next number in the sequence: "-1, 1, 4, 8, 13, ..."

Afina-wow [57]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

1. A-Tunes requires a membership fee of $12 a month and $1 for each download.

matrenka [14]

<h3>Answer:</h3>

After 16 downloads the charges will equal each other.

<h3>Step-by-step explanation:</h3>

First set up an equation

x = Downloads

12 + 1x = 5 + 1.5x

Solve

12 + 1x = 5 + 1.5x <- Rewrite your equation

-5 -5 <- Subtract 5 from both sides

8 + 1x = 1.5x <- Simplify

-1x -1x <- Subtract 1 from both sides

8 = 0.5x <- Simplify

8 = 1/2x <- Convert 0.5 to a fraction to make the next step easier

16 = x <- Multiply both sides by 2 to divide by

a fraction

4 0

3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

I need to the anser to 4 times 6c

faltersainse [42]

Answer:

24c

Step-by-step explanation:

I see 4 times 6c, which is,

24c

Hope this helps!!

5 0

3 years ago

A researcher decides to split scores on an exam into quartiles. She determines that a score of 64 is at the 25th percentile, a s

allochka39001 [22]

Answer:

Answer : A

Step-by-step explanation:

The given data is 25 th percentile is 64, 50th percentile is 74 and 75 th percentile is 80.

percentage : 25 50 75

score : 64 74 80

Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is odd, then the median is observation

$(\frac{n+1}{2}) ^{th}$ term

If the number of observations is even, then the median is observation and observations.

$(\frac{n}{2}+1) ^{th}$

given n=3, middle term is '74'

In this given data the median is (M) = 74

Interquartile range IQR = median of upper half-median of lower half

= 80-64

= 16

IQR = 16

8 0

3 years ago