Question

PLEASE HELP ASAP!! WILL GIVE BRAINLIEST!!

Answer 1

Given is :

The area of the rectangular patio is = 130 square feet

Let the width of the patio be = x feet

As length is 3 feet more than the width, so the length is = x+3 feet

Now area of rectangle is = length * width

$x(x+3)=130$

$x^{2}+3x=130$

$x^{2}+3x-130=0$

$x^{2}+13x-10x-130=0$

$x(x+13)-10(x+13)=0$

$(x-10)(x+13)=0$

This gives either x-10=0 or x+13=0

x-10=0 ; x=10

x+13=0 ; x=-13 (neglect this negative value)

So, the width of the patio is = 10 feet

Length = 10+3 = 13 feet