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Leona [35]
3 years ago
7

How do you know if something is a property or not?

Chemistry
1 answer:
Georgia [21]3 years ago
5 0
<span>It will have a little coma on top of the word, And if its not then it wouldn't have a coma at all.</span><span />
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Gravity is responsible for the
Degger [83]
Orbiting path of planets
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3 years ago
The ionic radius of S2- ion is larger than that of Cl- ion. Why?
Tresset [83]

Answer: A sulfur ion has more electron shells than a chlorine ion.

5 0
2 years ago
Check the statements that are accurate. Check all of the boxes that apply. Before Thomson’s experiments, scientists accepted tha
elixir [45]
Answer 1) It is incorrect.

Explanation : For the statement; 

Thomson did experiments with cathode ray tubes  to show that all atoms contain tiny negatively charged subatomic particles called as electrons<span>.

So the statement should be like this:
AFTER the </span><span>Thomson’s experiments, scientists accepted that the atom was made up of smaller particles.

Answer 2) This is correct.

Explanation : Rutherford was the scientist who discovered that atoms has volume is because of the empty spaces inside it. He did the gold foil experiments to prove this and he was successful in doing this by concluding that tiny dense empty places are occupied by positively charged nucleus.

Answer 3) This is Correct.

Explanation : After Thomson and Rutherford, Millikan also performed an experiment to prove that an atom contains a small positively charged nucleus which is usually surrounded by negatively charged electrons by his oil drop experiment.</span>
5 0
4 years ago
Write the charge balance for an aqueous solution of arsenic acid, H3AsO4, in which the acid can dissociate to H2AsO24 , HAsO24 2
lilavasa [31]

Answer:

Kindly check the explanation section.

Explanation:

When the Arsenic acid,H3AsO4 is put in water it dissociates to form or give out 1 proton, 2 protons or 3 protons that is 1H^+, 2H^+ and 3H^+. Check the equation showing the dissociation reactions as given below;

H3AsO4 ===========> H^+ + AsO4^-

H3AsO4 ===========> 2H^+ + AsO4^2-

H3AsO4 ===========> 3H^+ + AsO4^3-

Therefore, the total charge balance is given as:

[H^+] =[OH^-] + [ AsO4^-] + 2[ AsO4^2-] + 3[ AsO4^3-].

Kindly note that the [OH^-] is from water.

8 0
3 years ago
78.6 grams of O2 and 67.3 grams of F2 are placed in a container with a volume of 40.6 L. Find the total pressure if the gasses a
saul85 [17]

1) List the known and unknown quantities.

<em>Sample: O2.</em>

Mass: 78.6 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K.

<em>Sample: F2.</em>

Mass: 67.3 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K.

2) Find the pressure of O2.

<em>2.1- List the known and unknown quantities.</em>

<em>Sample: O2.</em>

Mass: 78.6 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

<em>2.2- Convert grams of O2 to moles of O2.</em>

The molar mass of O2 is 31.9988 g/mol.

mol\text{ }O_2=78.6\text{ }g*\frac{1\text{ }mol\text{ }O_2}{31.9988\text{ }g\text{ }O_2}=2.46\text{ }mol\text{ }O_2

<em>2.3- Set the equation.</em>

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

PV=nRT

<em>2.4- Plug in the known quantities and solve for P.</em>

(P)(40.6\text{ }L)=(2.46\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(316.28\text{ }K)

<em>.</em>

P_{O_2}=\frac{(2.46\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(316.28\text{ }K)}{40.6\text{ }L}P_{O_2}=1.57\text{ }atm

<em>The pressure of O2 is 1.57 atm.</em>

3) Find the pressure of F2.

<em>3.1- List the known and unknown quantities.</em>

<em>Sample: F2.</em>

Mass: 67.3 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

3.2- <em>Convert grams of F2 to moles of F2.</em>

The mmolar mass of F2 is 37.9968 g/mol.

mol\text{ }F_2=67.3\text{ }g\text{ }F_2*\frac{1\text{ }mol\text{ }F_2}{37.9968\text{ }g\text{ }F_2}=1.77\text{ }mol\text{ }F_2

<em>3.3- Set the equation.</em>

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

PV=nRT

<em>3.4- Plug in the known quantities and solve for P.</em>

(P)(40.6\text{ }L)=(1.77\text{ }mol\text{ }F_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(316.28\text{ }K)

<em>.</em>

P_{F_2}=\frac{(1.77molF_2)(0.082057L*atm*K^{-1}*mol^{-1})(316.28K)}{40.6\text{ }L}P_{F_2}=1.13\text{ }atm

<em>The pressure of F2 is 1.13 atm.</em>

4) The total pressure.

Dalton's law - Partial pressure. This law states that the total pressure of a gas is equal to the sum of the individual partial pressures.

<em>4.1- Set the equation.</em>

P_T=P_A+P_B

4.2- Plug in the known quantities.

P_T=1.57\text{ }atm+1.13\text{ }atmP_T=2.7\text{ }atm

<em>The total pressure in the container is </em>2.7 atm<em>.</em>

5 0
1 year ago
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