Answer:
0.674 mol
Explanation:
Step 1:
Data obtained from the question.
Volume (V) = 4 L
Pressure (P) = 560 kPa
Temperature (T) = 127°C
Number of mole (n) =?
Step 2:
Conversion to appropriate unit.
For pressure:
101.325 KPa = 1 atm
Therefore, 560 kPa = 560/101.325 = 5.53 atm
For temperature:
Temperature (Kelvin) = temperature (celsius) + 273
temperature (celsius) = 127°C
Temperature (Kelvin) = 127°C + 273 = 400K
Step 3:
Determination of the number of mole of Neon.
The number of mole of Neon can be obtained by using the ideal gas equation as follow:
Volume (V) = 4 L
Pressure (P) = 5.53 atm
Temperature (T) = 400K
Gas constant (R) = 0.082atm.L/Kmol
Number of mole (n) =?
PV = nRT
5.53 x 4 = n x 0.082 x 400
Divide both side by 0.082 x 400
n = (5.53 x 4) /(0.082 x 400)
n = 0.674 mol
The number of mole of Neon is 0.674 mol
