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Karo-lina-s [1.5K]
3 years ago
15

Suppose that 7% of the general population has a disease and that the test for the disease is accurate 70% of the time. What is t

he probability of testing positive for the disease?
Mathematics
2 answers:
zmey [24]3 years ago
5 0

Answer: 0.328

Step-by-step explanation:

Given: The percent of general population has a disease = 7%

⇒ The percent of general population  has no disease = 100\%-7\%=93\%

Also, The test for the disease is accurate 70% of the time.

Probability that test is accurate = 0.7

⇒ The test for the disease is not accurate 30% of the time.

Probability that test is not accurate = 0.3

Now, the probability of testing positive for the disease is given by :-

0.07\times0.7+0.93\times0.3=0.328

strojnjashka [21]3 years ago
4 0
You have a 4.9 percent chance of testing positive. Hope this helped!

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2.01 is the total for three oranges.

the math would be 2.01 ÷ 3 = 0.67

to check your answer:

if one orange equals 0.67 and you have three of them

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2 years ago
ASAP: I need as soon as possible with this question I have taken a picture of. If you could tell me how to do it and the answer,
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Answer:

The answer to your question is h = 125.85 ft = 126 ft

Step-by-step explanation:

Process

1.- Determine two equations to solve the problem

    tan 14 = \frac{h}{x}                     (1)

    tan 47 = \frac{h}{x - 386}           (2)

    from (1)                           h = xtan14

    substitute in (2)             tan 47 = \frac{xtan14}{x - 386}

    solve for x                     tan47(x - 386) = xtan14

                                          1.07x - 413.9 = 0.25x

                                          1.07x - 0.25x = 413.9

                                           0.82x = 413.9

                                           x = 413.9/0.82

                                           x = 504.76 ft

2.- Calculate h

                                          h = 504.76 tan 14

                                          h = 125.85 ft = 126 ft

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