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inn [45]
4 years ago
6

What is a slope of -1

Mathematics
1 answer:
suter [353]4 years ago
5 0
It means that for every 1 unit the line goes down, the line goes 1 unit to the right
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What if we draw three socks from the box instead. what is the probability that we draw a matching pair? (having all three socks
frutty [35]

There is a chance of 1/16*1/15 that she gets the specific socks pair according to laws of probability and the counting principle but thats not how it will work over here.

As we should be guaranteed that she gets the number of socks she obviously must take out around 9 socks as we are taking the worst case scenario where all the socks that come out are the different ones so the ninth sock must match any of the others.

But if we draw three socks obviously the probability is 1/16*1/15*13/14 as we dont want the third one to be same. We can multiply the answer by 3 as it can be in three different orders.

8 0
4 years ago
The graph below shows a transformation, g(x), of the parent function, f(x) = 2^x. Which TWO statements describe the relationship
lianna [129]
This is my answer - a beautiful image. You haven’t attached the image to determine the answer, please do!

8 0
3 years ago
Cual es la amplitud de estos conjuntos de datos 12,16,48,64,36,48,12,32,y 48
nalin [4]
Answer:









Step-by-step explanation:
8 0
3 years ago
Write a real world problem where the Unit rate is 6 miles per hr
Galina-37 [17]
This is just an example i came up with randomly:

Emma is going somewhere for vacation. Emma has been traveling for 6 hours and in those 6 hours, she has travelled 36 miles. How many miles did she travel in one hour?
8 0
3 years ago
Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1
algol [13]

Find the critical points of f(x,y):

\dfrac{\partial f}{\partial x}=-2x=0\implies x=0

\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12

All three points lie within D, and f takes on values of

\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}

Now check for extrema on the boundary of D. Convert to polar coordinates:

f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t

Find the critical points of g(t):

\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0

\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2

\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi

where n is any integer. There are some redundant critical points, so we'll just consider 0\le t< 2\pi, which gives

t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3

which gives values of

\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}

So altogether, f(x,y) has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0
3 years ago
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