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2 years ago

6

The graph below shows a transformation, g(x), of the parent function, f(x) = 2^x. Which TWO statements describe the relationship

between g(x) and f(x)? (See attached image)

1 answer:

lianna [129]2 years ago

8 0

This is my answer - a beautiful image. You haven’t attached the image to determine the answer, please do!

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Leyla drops a penny from a height of 150m.

dusya [7]

Asked and answered elsewhere.
brainly.com/question/9071599

5 0

2 years ago

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

3 0

3 years ago

Read 2 more answers

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago

Y = f(x) = 16x Find f(x) when x = 1/2

Alina [70]

Answer:

The answer depends on what the problem really is.

f(1/2) = 8

or

f(1/2) = 4

See below.

Step-by-step explanation:

This is the problem as it was posted:

y = f(x) = 16x

Let x = 1/2

y = f(1/2) = 16(1/2) = 8

Perhaps the problem is this:

$y = f(x) = 16^x$

If x is an exponent of 16 and not a factor, then the answer is:

$y = f(\frac{1}{2}) = 16^\frac{1}{2} = \sqrt{16} = 4$

5 0

3 years ago

Help........Write an equation and solve:

Tom [10]

Answer:

5 months

Step-by-step explanation:

Equate the formulas for the weights of the two boys:

J's weight = 120 lb + (10 lb/mo)m = D's weight = 150 lb + (4 lb/mo)m

Solve as follows: Subtract 120 lb from both sides:

(10 lb/mo)m = 30 lb + (4 lb/mo)m.

Then: (6 lb/mo)m = 30 lb, and m = (30 lb) / (6 lb/mo) = 5 months

3 0

3 years ago