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Greeley [361]
1 year ago
10

What is the value of x in the equation 1/5x-2/3y = 30, when y = 15?

Mathematics
2 answers:
Nataly [62]1 year ago
8 0

Answer:

x = 200

Step-by-step explanation:

Given equation:

\sf \dfrac{1}{5}x-\dfrac{2}{3}y=30

<u><em>Steps:</em></u>

1. Substitute 15 as the value of y in the equation:

\sf \dfrac{1}{5}x-\dfrac{2}{3}(15)=30\ \textsf{[ multiply ]}\\\\\Rightarrow \dfrac{1}{5}x-\dfrac{30}{3}=30\ \textsf{[ simplify ]}\\\\\Rightarrow \dfrac{1}{5}x-10=30

2. Add 10 to both sides:

\sf \dfrac{1}{5}x-10+10=30+10\\\\\Rightarrow \dfrac{1}{5}x=40

3. Multiply both sides by 5 to isolate x:

\sf 5\left(\dfrac{1}{5}\right)x=5(40)\\\\\Rightarrow x=200

4. Check your work:

\sf \dfrac{1}{5}x-\dfrac{2}{3}y=30\ \textsf{[ substitute 200 for x, and 15 for y ]}\\\\\dfrac{1}{5}(200)-\dfrac{2}{3}(15)=30\ \textsf{[ multiply ]}\\\\\dfrac{200}{5}-\dfrac{30}{3}=30\ \textsf{[ divide ]}\\\\40-10=30\ \textsf{[ subtract ]}\\\\30=30\ \checkmark

Learn more here:

brainly.com/question/12965239

Alika [10]1 year ago
3 0

Hey there!

  • Answer :

\boxed{\bold{\green{ x = 200}}}

\\

  • Explanation:

<u>Given </u><u>expression </u><u>:</u><u> </u>

\sf{ \frac{1}{5} \green{x} -  \frac{2}{3} \orange{y} = 30 }

1) <em>Substitue 15 for</em> \sf{\orange{y}} :

\sf{ \frac{1}{5} \green{x} -  \frac{2}{3} \orange{ \times 15} = 30 } \\  \\  \implies\sf{ \frac{1}{5} \green{x} -  \frac{30}{3}  = 30 }  \\  \\  \implies\sf{ \frac{1}{5} \green{x} -  10= 30 }

\\

2) Solve for x :

\sf{ \frac{1}{5} \green{x} -  10= 30 }

⇢<u>Add</u> 10 <u>to both sides of the equation</u> :

\sf{ \frac{1}{5} \green{x} -  10  \:  \bold{+  \: 10}= 30   \: \bold{+   \: 10 }}  \\  \\   \implies \sf{\frac{1}{5} \green{x} \:  = 40 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

⇢<u>Multiply both </u><u>sides</u><u> of the equation</u> by 5:

\Big( \dfrac{1}{5}  \green{x}\Big)  \: \bold{ \times  \: 5}=40  \: \bold{ \times \:  5} \\  \\  \implies  \sf{\dfrac{5}{5}  \green{x} \:  = 200} \\  \\   \implies   \green{ \boxed{\sf{x = 200}}}

\\

3) Let's check our answer by replacing \green{x} with 200 and \orange{y} with 15 :

\sf{\dfrac{1}{5}\overbrace{\green{\times \: 200}}^{\green{x}} - \dfrac{2}{3}\underbrace{\orange{\times \:15}}_{\orange{y}}= \dfrac{200}{5}  -   \dfrac{30}{30}  = 40 - 10 = \boxed{ 30} }

\\ \\

▪️Learn more about first-degree equations:

↣brainly.com/question/15154296

↣brainly.com/question/14700809

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