Question

In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.

Answer 1

Answer:

Step-by-step explanation:

Please see the picture attached also.

In triangle ABC, since two legs are given using Pythagorus theorem

we get AC = 5

We have triangle ABC and CHB having congruent angles

Hence they are similar and sides are proportional

$\frac{BH}{BC} =\frac{4}{5} \\BH=3(\frac{4}{5})\\BH=2.4$

In right angled triangle CHB, we have two sides.

Hence third side

CH =$\sqrt{3^2-2.4^2} \\=1.8$

Now AH = AC-CH

= 5-1.8

=3.2