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lisov135 [29]
4 years ago
5

the utility bill for the Millers home was it in April with $132 42% of the bill was for gas and the rest for electricity how muc

h does the Millers pay for gas and how much did they pay for electricity
Mathematics
2 answers:
Anit [1.1K]4 years ago
6 0
In the given question, there are several data of immense importance. based on these data's the answer to the question can be easily deduced. it is already given that the total utility bill for the month of April in Millers house is $132 and 42% of the bill was paid for gas. remaining amount is paid as electricity charges.
Now
Amount of money paid for gas = 132 * (42/100) dollars
                                                  = 5544/100 dollars
                                                   = 55.44 dollars
Then
The amount of money paid for electricity = (132 - 55.44) dollars
                                                                   = 76.56 dollars
So the Millers paid 55.44 dollars for gas and 76.56 dollars for electricity in the month of April.
postnew [5]4 years ago
6 0

Answer:

Step-by-step explanation:

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A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 4 cm and diameter of t
docker41 [41]

Answer:

See below ~

Step-by-step explanation:

<u>Things to Find</u>

  1. Volume of Toy
  2. Difference of Volumes in Cube and Toy
  3. Total Surface of Toy

<u>Volume of Toy</u>

  • Volume of Hemisphere + Volume (Cone)
  • 2/3πr³ + 1/3πr²h
  • 1/3πr² (2r + h)
  • 1/3 x 3.14 x 16 (8 + 4)
  • 1/3 x 50.24 x 12
  • 50.24 x 4
  • <u>200.96 cm³</u>

<u></u>

<u>Volume of Circumscribing Cube</u>

  • Edge length is same as diameter
  • V = (8)³
  • V = 512 cm³

<u>Difference in Volume</u>

  • 512 - 200.96
  • <u>311.04 cm³</u>

<u></u>

<u>Slant height of cone</u>

  • l² = 4² + 4²
  • l² = 32
  • l = 4√2 cm = 5.6 cm

<u />

<u>Surface Area of Toy</u>

  • CSA (hemisphere) + CSA (Cone)
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2 years ago
Points A,B,C and D are midpoints of the sides of the larger square. If the smaller square has area 60, what is the area of the b
kotykmax [81]

Answer:

80

Step-by-step explanation:

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3 years ago
I need help I will give BRAINLEST
GREYUIT [131]

Answer:

25%

Step-by-step explanation:

To solve this, we can use the percent change formula shown in the picture attached below. x_{2} is the new value, x_{1} is the old value, and C represents the change. For this problem, 80 is the new value and 64 is the old value. Let's plug those numbers into the formula and solve for the percent change:

C = \frac{(80-64)}{64} \\ × 100

C = \frac{16}{64} ×100

C = 0.25 ×100

C = 25%

Thus, the answer is 25%.

7 0
3 years ago
Rewrite the following integral in spherical coordinates.​
lora16 [44]

In cylindrical coordinates, we have r^2=x^2+y^2, so that

z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}

correspond to the upper and lower halves of a sphere with radius \sqrt2. In spherical coordinates, this sphere is \rho=\sqrt2.

1 \le r \le \sqrt2 means our region is between two cylinders with radius 1 and \sqrt2. In spherical coordinates, the inner cylinder has equation

x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)

This cylinder meets the sphere when

x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)

which occurs at

\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi

where n\in\Bbb Z. Then \frac\pi4\le\phi\le\frac{3\pi}4.

The volume element transforms to

dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi

Putting everything together, we have

\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3

4 0
2 years ago
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