The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:

Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
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Answer:
(From left to right) 2 5 8
Step-by-step explanation:
1. Find the gap (between the first and last terms) 11 - (-1) = 12
2. Divide by the number of times the linear term is added: 12/4=3
3. Use the common difference to find the missing values.
14=6+2x
subtract 6 from both sides
8=2x
divide both sides by 2
x=4 candy bars
Plug in the to X value in
The recurring decimal number 9.2424... expressed in mixed number is 
In the given decimal number, 2 is the digit at the tenth place and 4 is the digit at the hundredth place.
The fraction part
in the simplest form is 
The whole number part is 9.
Therefore, the number 9.2424... as a mixed number in the simplest form is 