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frosja888 [35]
3 years ago
10

Simon says "five time my age 4 years ago is the same as three time my age in 2 years" how old is simon

Mathematics
1 answer:
omeli [17]3 years ago
7 0

Simon is 13 years old

Let x be Simon's age

Thus 4 years ago his age was (x - 4) and 2 years from now his age is (x + 2)

Hence 5(x - 4) = 3(x + 2)

distributing both sides gives

5x-20 = 3x + 6

subtract 3x from both sides of the equation

5x - 3x - 20 = 6

2x - 20 = 6

add 20 to both sides

2x = 6 + 20 = 26

divide both sides by 2

x = \frac{26}{2} = 13

Simon is 13 years old


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Hello, Brainly community!
ioda

Answer:

(B)  \displaystyle \frac{W(3.1) - W(2.9)}{0.2}

General Formulas and Concepts:

<u>Calculus</u>

Limits

Derivatives

  • The definition of a derivative is the slope of the tangent line.

Derivative Notation

Instantaneous Rates

  • Tangent Line: \displaystyle f'(x) = \frac{f(b) - f(a)}{b - a}

Step-by-step explanation:

Since we are trying to find a <em>rate</em> at which W(t) changes, we must find the <em>derivative</em> at <em>t</em> = 3.

We are given 2 close answer choices that would have the same <em>numerical</em> answer but different <em>meanings</em>:

  1. (A)  \displaystyle  \lim_{t \to 3} W(t)
  2. (B)  \displaystyle \frac{W(3.1) - W(2.9)}{0.2}

If we look at answer choice (A), we see that our units would simply just be volume. It would not have the units of a rate of change. Yes, it may be the closest numerically correct answer, but it does not tell us the <em>rate</em> at which the volume would be changing and it is not a derivative.

If we look at answer choice (B), we see that our units would be cm³/s, and that is most certainly a rate of change. Answer choice (B) is also a <em>derivative</em> at <em>t</em> = 3, and a derivative tells us what <em>rate</em> something is changing.

∴ Answer choice (B) will give us the best estimate for the value of the instantaneous rate of change of W(t) when <em>t</em> = 3.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

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