Find the area of the trapezoid.

Mathematics

2 answers:

solong [7]3 years ago

5 0

Add top and bottom number, divide by 2 then multiply by the height:

18 +6 = 24

24/2 = 12

12 * 12 = 144 square inches

Vadim26 [7]3 years ago

4 0

Area of the trapezium = 1/2(18 + 6) x 12
Area of the trapezium = 144 in²

------------------------------------------------
Answer: Area = 144 in²
------------------------------------------------

You might be interested in

Find the limit if it exists lim x→0 sqrtx+7-sqrt7 over x

Triss [41]

Answer:

$\frac{1}{ 2\sqrt{7} }$

Step-by-step explanation:

$\lim_{x\to 0} \frac{ \sqrt{x + 7} - \sqrt{7} }{x} \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} - \sqrt{7}) }{x} \times \frac{( \sqrt{x + 7} + \sqrt{7}) }{( \sqrt{x + 7} + \sqrt{7}) } \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} )^{2} - (\sqrt{7})^{2} }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{( {x + 7} - {7}) }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {\cancel x}}{\cancel x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {1}}{\sqrt{x + 7} + \sqrt{7}} \\ \\ = \frac{1}{ \sqrt{0 + 7} + \sqrt{7} } \\ \\ = \frac{1}{ \sqrt{7} + \sqrt{7} } \\ \\ = \frac{1}{ 2\sqrt{7} }$

6 0

3 years ago

Mark ran 213 mi. and Shaun ran 315 mi. Find the difference in the distance that they ran.

Nutka1998 [239]

102 miles you subtract them and get the results

3 0

2 years ago

Write the perimeter of each figure as a trinomial. Must show your work.

noname [10]

Answer:

P = 2n + 8m - 1

Step-by-step explanation:

A trinomial is an expression or equation that has three terms. A term is when between the numbers or variables, the operations are neither subtraction nor addition, or when there is only one number.

If two terms have the same variable, called like terms, they can be combined by addition or subtraction.

The perimeter is the total length of all the sides.

The formula for the perimeter of a triangle is $P = s_{1} + s_{2} + s_{3}$ for each of the three sides.