Answer:
P = 1 (14,045 ± 0.03 ) k gm/s
Explanation:
In this exercise we are asked about the uncertainty of the momentum of the two carriages
Δ (Pₓ / Py) =?
Let's start by finding the momentum of each vehicle
car X
Pₓ = m vₓ
Pₓ = 2.34 2.5
Pₓ = 5.85 kg m
car Y
Py = 2,561 3.2
Py = 8,195 kgm
How do we calculate the absolute uncertainty at the two moments?
ΔPₓ = m Δv + v Δm
ΔPₓ = 2.34 0.01 + 2.561 0.01
ΔPₓ = 0.05 kg m
Δ
= m Δv + v Δm
ΔP_{y} = 2,561 0.01+ 3.2 0.001
ΔP_{y} = 0.03 kg m
now we have the uncertainty of each moment
P = Pₓ /
ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²
ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²
ΔP = 0.006 + 0.0026
ΔP = 0.009 kg m
The result is
P = 14,045 ± 0.039 = (14,045 ± 0.03 ) k gm/s
Well i think the best answer would be A
Answer:
A
Explanation:
absolute magnitude and luminosity vs the spectral position/ temperature
In order to indicate that ones business is indeed
successful, you need to look into the following characteristics:
<span>·
</span>Planning
– oversee the possible mistakes and create plan Bs. Know the company’s
statement of purpose, goals, etc.
<span>·
</span><span>Evaluation
– assess the plan after its pilot test for area of improvement</span>
Answer:
If the sphere is made of a non-conducting material, charges can´t distribute freely over its surface or volume. In non-conducting material bodies, charges can be transported from a molecule to another nearest to it. Therefore if you rub an object with a positive charge with this sphere made of non-conducting plastic, the object will rip some negative charges (electrons) of that zone of the sphere. Therefore that zone will get a superficial positive charge density, but the non-affected zone of the sphere will keep having a null charge density.
