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3 years ago

As fast as possible pls answer my doubt I think it is d

Physics

1 answer:

notka56 [123]3 years ago

3 0

Answer:

B. From the light due to the explosion

Explanation:

Space is basically a vacuum, meaning it is void of matter or to be more accurate, the matter are very far apart. Now sound and vibrations need matter for them to travel through. Sound is also a type of vibration, and they can only travel through a medium (made up of matter) for them to move along. Since the astonaut is in space, then he won't feel vibrations or hear the sound of the expolosion..

On the other hand, light is an EM wave or an electromagnetic wave. Electromagnetic waves can travel through a vacuum. So the answer would be B.

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Se lanza una piedra de 3.00 N verticalmente hacia arriba desde el suelo. Se observa que, cuando está 15.0 m sobre el suelo, viaj

BARSIC [14]

Answer:

(a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Explanation:

Given that,

Weight of stone = 3.00 N

Height = 15 m

Speed = 25.0 m/s

(a). We need to calculate the speed at the moment of being thrown

Using work energy theorem

$W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)$

$-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)$

Put the value into the formula

$-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)$

$-2\times9.8\times15=25^2-v_{1}^2$

$-v_{1}^2=-300-25^2$

$v_{1}=\sqrt{925}$

$v_{1}=30.41\ m/s$

(b). We need to calculate the maximum height

Using work energy theorem

$[tex]W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2$

$mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2$

Here, $\dfrac{1}{2}mv_{2}^2$ =0

$-(mg)\times d=\dfrac{1}{2}mv_{1}^2$

$d=\dfrac{v_{1}^2}{2g}$

Put the value into the formula

$d=\dfrac{30.41^2}{2\times9.8}$

$d=47.18\ m$

Hence, (a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

6 0

3 years ago

Wegut.

AVprozaik [17]

We/Wm = ge/gm = 120N/1.2N

gm = ge/100 = 0.1 m/s^2

density = mass/volume = 3M/(4pir^3)

Re-arranging this equation, we get

M/r^2 = (4/3)×pi×(density)×r

From Newton's universal law of gravitation, the acceleration due to gravity on the moon gm is

gm = G(M/r^2) = G×(4/3)×pi×(density)×r

Solving for density, we get the expression

density = 3gm/(4×pi×G×r)

= 3(0.1)/(4×3.14×6.67×10^-11×2.74×10^6)

= 130.6 kg/m^3

6 0

3 years ago

What is the process that changes smaller atoms into larger ones in a star

Alisiya [41]

Answer:

Nuclear fusion

Explanation:

In fusion, many nuclei (the centers of atoms) combine together to make a larger one (which is a different element). ... A star's mass determines what other type of nucleosynthesis occurs in its core (or during explosive changes in its life cycle).

5 0

3 years ago

how much voltage is in the primary coil if there are 3200 winding in the secondary coil 500 winding in the primary and 25v in th

Tema [17]

Answer:

Voltage in the primary winding of the coil is 3.9 V

Explanation:

As we know by the principle of transformer we have

$\frac{V_s}{V_p} = \frac{N_s}{N_p}$