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PIT_PIT [208]
3 years ago
10

if a bowling ball hits a wall a force of 6 N, the wall exerts a force of how much back. on the bowling ball

Physics
1 answer:
grigory [225]3 years ago
3 0
It would exert the same back right?
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Define Momentum in detail.
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Explanation:

Momentum Is defined as the product of of mass and its velocity

Momentum (M) =mass *velocity

SI unit of momentum is kgm/s

The rate of change in momentum

=change in momentum / time

=(mv-mu)/t

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A car passes you at 18 m/s to the north and increases its speed at a rate of 3.0 m/s. Determine the car's velocity when it has a
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Two objects, P and Q, have the same mo-<br> mentum. Q can have more kinetic energy<br> than P if it:
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If you increase the distance by double the work will _____________
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Answer: the work will also increase by double

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3 years ago
awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall
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Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

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Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

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momentum conservation along x direction

m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}

now plug in all values in it

1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22

so we have

3.01 = 0.375v_1 + 0.927v_2

similarly in Y direction we have

m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}

now plug in all values in it

0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22

so we have

0 = 0.927v_1 - 0.375v_2

v_2 = 2.47 v_1

now from 1st equation we have

3.01 = 0.375 v_1 + 0.927(2.47 v_1)

v_1 = 1.13 m/s

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so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

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initial kinetic energy = final kinetic energy

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KE = 6.66 J

5 0
3 years ago
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