The solution you should use is Hooke's law: F=-kx
It should have the same signs because they repel due to the stretch of the spring.
a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be
<span>F = kx
270 N/m x 0.38 m = 102.6 N
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b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force.
When resistance is constant, current is proportional to voltage. When 1/3 the voltage is applied, 1/3 the current will result.
(1/3)*(1.2 A) = 0.4 A
The resulting current will be 0.4 A.
Answer:
C)
Explanation:
The buoyancy and weight of the wood have to be equal for the system to be in equilibrium. The total mass (then, weight) of the wood is the same, so the total buoyancy has to be the same. Since buoyancy is the weight of the liquid displaced, the volume of liquid displaced will be the same in either case, which means that the water level will remain unchanged.
Answer:
So it will lift the mass by h = 17 m
Explanation:
As per energy conservation we know that
here we know that
now we have
so work done by the engine is 250 J
now we have
