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3 years ago

9

Ignore my working out but is it right

1 answer:

marissa [1.9K]3 years ago

3 0

Good job u got the answer right

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A weather balloon is launched from the ground at a location that is 750 feet from a 65 foot royal palm tree. What is the minimal

Sonbull [250]

Answer: 5°

Step-by-step explanation:

You can use a right triangle to solve

Hypotenuse would be the flight path

One leg (opposite) is the tree 65 ft

Tan (Θ) = opposite/ adjacent = 65/750

Θ = arctan (65/750)

Θ = 5°

4 0

2 years ago

Second street bank charges an overdraft fee of $35.00 for insuficient funds transactiond. Malcom's check register showed up bala

Leya [2.2K]

He will have enough money in his bank to avoid an insufficient fund charge because when you add 250+36.21+94.30 it equals 380.51. He had 386.49 in his account before he withdrawal that money, so he still had money in his account when he got money out.

4 0

3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

Can somebody help with this!!!! please.

kvasek [131]

Answer:

2(x-3)(x-1)

Step-by-step explanation:

2(x+x+3)

2(x-3)(x-1)

8 0

3 years ago

Read 2 more answers

What would you multiply the fraction 12/28 by to make the product equal 1?

Grace [21]

it's 21/21 which would simplify to 1

How I got that answer was by multiplying 3/7 and 7/3 to get 21 both times

8 0

3 years ago