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Akimi4 [234]
3 years ago
7

Two angles form a complementary pair (sum is 90 degrees) one angle is 3x - 10 and the other angle is x + 8. Write an equation an

d solve for each angle.
Could somebody help? Thank you :)

Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0
3x-10+x+8=90
4×-2=90
4x=92
X=23

One angle is 31. 23+8
The second one is 59. 3 (23)-10
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Step-by-step explanation:

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State the domain of the relation.
gogolik [260]

Answer:

The Domain of the relationship is the set: {-3, -2, -1, 0, 1, 2} (Answer B)

Step-by-step explanation:

Let's recall that the Domain of a relationship is the set of values in the starting set for which there is a correspondent value in the final set.

In this case, we have a set of numbers on the x axis, which are connected with values in the y axis as indicated by the plotting of the points on the (x,y) plane.

The Domain will consist of all those x-values for which we see in the given plot connected to a corresponding y-value.

So, we see that:

the x-value -3 is connected to the y-value -4

the x-value -2 is connected to the y-value -3

the x-value -1 is connected to the y-value -1

the x-value 0 is connected to the y-value 0

the x-value 1 is connected to the y-value 3

and the x-value 2 is connected to two y-values:  4 and 5

Therefore all those x-values are part of the Domain of this relationship. That is, the set: {-3, -2, -1, 0, 1, 2}

7 0
3 years ago
NEED IT ASAP<br> what’s is the quotient<br> 2 1/5<br> ———<br> -1/10
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Find the polynomial function
laiz [17]

Answer:

y = 2x³ +x² -3x +6

Step-by-step explanation:

The polynomial correlation function of a graphing calculator can work with the table of function values to give you the equation. (See attached)

_____

If you want to solve this by hand, you can write the equations for the unknown coefficients in the polynomial function, then solve those. First of all, notice that you are given the y-intercept, (0, 6), so you know one of the coefficients already. That leaves a system of 3 equations in 3 unknowns that need to be solved.

___

<em>Writing the equations</em>

... ax³ +bx² +cx +6 = y . . . . the generic linear equation in a, b, c that you're writing

For x = -1:

... -a +b -c +6 = 8

For x = 1

... a + b + c + 6 = 6

For x = 2

... 8a +4b +2c +6 = 20

In augmented matrix terms, this set of linear equations looks like ...

\left[\begin{array}{ccc|c}-1&1&-1&2\\1&1&1&0\\8&4&2&14\end{array}\right]

___

<em>Solving the equations</em>

There are a number of ways to solve these. Again, a graphing calculator often has solution functions, such as reducing a matrix to row-echelon form, that will solve this in a keystroke or two.

If you add the first two equations, you get ...

... 2b = 2 ⇒ b = 1

Substituting that into the first equation allows you to simplify it to ...

... -a -c = 1

Dividing the third equation by 2 (and substituting for b) makes it ...

... 4a +c = 5

Adding these equations gives ...

... 3a = 6 ⇒ a = 2

Then ...

... c = -a -1 = -2 -1 = -3

And our polynomial function is ...

... y = 2x³ +x² -3x +6

7 0
3 years ago
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