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2 years ago

11

In a fruit cocktail, for every 15 ml of orange juice you need 25 ml of apple juice and 10 ml of coconut milk. What proportion of

the cocktail is coconut milk? Give your answer as a fraction in its simplest form

1 answer:

Keith_Richards [23]2 years ago

6 0

Answer:
1/5

reason:

if there are 15ml of orange juice, that means there has to be 25ml of apple juice and 10ml of coconut milk
that means the total amount of cocktail there is equals 50ml
10ml is 1/5 of 50ml, which means 1/5 of the cocktail is made of coconut milk

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Can I please have the answers.

Brums [2.3K]

Question 22.). Write the equation in Standard Form:

10y = 12x + 0.7

Identify: A, B, C

Standard Form for Linear Equation: Ax + By = C

10y = 12x + 0.7

The Standard Form of the solution is

Ax + By = C, Where, A ≥ 0

A and B, are Non- Zero numbers.

Therefore, Your answer, Letter Choice, (D), 120x - 100y = - 7, Where,

A = 120, B = - 100, and C = - 7

Question 24.). Described as, Inconsistent, Consistent, and Independent, Consistent, and Dependent, or None of These.

9x - 8y = 15, and 27x - 24y = 3

Solve:

9x - 8y = 15; 27x - 24y = 3

Steps: I will try to solve the system of equation:

9x - 8y = 15; 27x - 24y = 3

Step, Solve: 9x - 8y = 15 for x

9x - 8y + 8y = 15 + 8y

Add 8y to both sides:

9x = 8y + 15

9x/9 = 8y + 15/9 ( Divide both sides by 9):

x = 8/9y + 5/3

Step Substitute:

8/9y + 5/3 for X in 27x - 24y = 3

27x - 24y = 3

27 ( 8/9y + 5/3) - 24y = 3

45 = 3

Simplify Both sides of equation:

45 + - 45 = 3 + - 45 ( Add - 45, to both sides.):

0 = - 42

Therefore, No real Solutions, to both Equation.

Hence; 9x - 8y = 15; and 27x - 24 = 3, have No Real Solutions, and Therefore, They are, Answer Letter Choice, (B), Inconsistent.

Hope that helps!!! Sorry, I couldn't figure out Number (23.). : )

8 0

3 years ago

To calculate the cost of painting his silo, a farmer must find its height. The farmer uses a cardboard square to line up the top

tankabanditka [31]

Answer:

Height of the silo = 18 feet.

Step-by-step explanation:

From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.

Farmer is standing at 8 ft distance from the silo.

From triangle AEC,

tan(∠CAE) = $\frac{CE}{AE}$

= $\frac{5}{8}$

m(∠CAE) = $tan^{-1}(\frac{5}{8})$

= 32°

m∠BAE = 90° - 32° = 58°

From the triangle ABE,

tan58° = $\frac{BE}{AE}$

BE = 8tan58°

BE = 12.8 ft

Total height of the silo = BE + EC

= 12.8 + 5

= 17.8

≈ 18 ft

Therefore, total height of the silo is 18 ft.

3 0

2 years ago

Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam

MariettaO [177]

$X-(A\cup B)=(X-A)\cap(X-B)$

I'll assume the usual definition of set difference, $X-A=\{x\in X,x\not\in A\}$ .

Let $x\in X-(A\cup B)$ . Then $x\in X$ and $x\not\in(A\cup B)$ . If $x\not\in(A\cup B)$ , then $x\not\in A$ and $x\not\in B$ . This means $x\in X,x\not\in A$ and $x\in X,x\not\in B$ , so it follows that $x\in(X-A)\cap(X-B)$ . Hence $X-(A\cup B)\subset(X-A)\cap(X-B)$ .

Now let $x\in(X-A)\cap(X-B)$ . Then $x\in X-A$ and $x\in X-B$ . By definition of set difference, $x\in X,x\not\in A$ and $x\in X,x\not\in B$ . Since $x\not A,x\not\in B$ , we have $x\not\in(A\cup B)$ , and so $x\in X-(A\cup B)$ . Hence $(X-A)\cap(X-B)\subset X-(A\cup B)$ .

The two sets are subsets of one another, so they must be equal.

$X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)$

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices $i\in I$ .

Proof of one direction for example:

Let $x\in X-\left(\bigcup\limits_{i\in I}A_i\right)$ . Then $x\in X$ and $x\not\in\bigcup\limits_{i\in I}A_i$ , which in turn means $x\not\in A_i$ for all $i\in I$ . This means $x\in X,x\not\in A_{i_1}$ , and $x\in X,x\not\in A_{i_2}$ , and so on, where $\{i_1,i_2,\ldots\}\subset I$ , for all $i\in I$ . This means $x\in X-A_{i_1}$ , and $x\in X-A_{i_2}$ , and so on, so $x\in\bigcap\limits_{i\in I}(X-A_i)$ . Hence $X-\left(\bigcup\limits_{i\in I}A_i\right)\subset\bigcap\limits_{i\in I}(X-A_i)$ .

4 0

2 years ago

In a group of 58 learners at Nakambuda C.S, 34 learners have chosen the field of Agriculture. What fraction of learners will be

asambeis [7]

learners of Agriculture: 34/58

semplify it

divide by 2

34 > 17

58 > 29

they are prime numbers, so can't be semplify anymore

17/29 will do Agriculture

in percentage we have a proportion:

17 : 29 = x : 100

x = (17 * 100) / 29 = 1700 / 29 ≅ 48,62

4 0

2 years ago

Five more than the product of a number and 4 is equal to 8

Maru [420]

Answer:

$4x+5=8$

$x=\frac{3}{4}$

Step-by-step explanation:

Let

x ---> the number

we know that

The algebraic expression is equal to multiply the number by 4, add 5 and equal 8

so

$4x+5=8$

Solve for x

subtract 5 both sides

$4x=8-5\\4x=3$

Divide by 4 both sides

$x=\frac{3}{4}$

3 0

3 years ago