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natali 33 [55]
3 years ago
14

Simplify and show your work -8 + 4i / 4 - 4i

Mathematics
1 answer:
zhenek [66]3 years ago
7 0
=  ( -8 + 4i ) / (4 - 4i ) = 4(-2 + i )  /  4( 1- i ) = ( -2 + i )  /  ( 1 - i )
=  (i  - 2  )(-i +1)^-1
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Answer is 
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Read 2 more answers
Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic
Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

b) s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

c) For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

SS = \sum_{i=1}^n (X_i -\bar X)^2

And the sample variance for this case can be calculated from this formula:

s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

8 0
3 years ago
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