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marishachu [46]
3 years ago
8

The following triangle is and .

Mathematics
1 answer:
devlian [24]3 years ago
8 0

Answer: By angle it is right angle triangle and by side it is isoceles triangle

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The new total is $60, but the sales tax is 5 % of my bill. How much is the sales tax
Dimas [21]

3 dollars. You take 60 and multiply it by 5%

8 0
3 years ago
A quadrilateral has vertices A{11, -7), B(9,-4), C11,-1), and D(13,-4).
Bess [88]

Answer:

Quadrilateral ABCD is a <u>parallelogram</u>

if the vertex C( 11, -1 ) we’re shifted to the point C ( 11, 1 ), quadrilateral ABCD would be a <u>kite</u>

Step-by-step explanation:

without solving, im guessing that quad ABCD is a paralellogram (//gram)

lets test this theory

see if the slope of AB and CD, and BC and AD is the same

slope AB and CD

AB:

-7--4/11-9

=-3/2

CD:

-1--4/11-13

=3/-2

=-3/2

slope is the same

slope BC and AD

BC:

-4--1/9-11

=-3/-2

=3/2

AD:

-7--4/11-13

=-3/-2

=3/2

slope is same

because 2 pairs // sides ---> //gram

if the vertex C( 11, -1 ) we’re shifted to the point C ( 11, 1 ), quadrilateral ABCD would be a kite

hope this helps!

please mark brainliest thank you !

4 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
Mr. Ishimoto needs to replace the grass in the section of his lawn that is shown below.
tatiyna

Answer:

The replacing the grass will cost  Mr. Ishimoto $14.00.

Step-by-step explanation:

The area of a rectangular field is:

\text{Area}=\text{height}\times \text{base}

It is provided that Mr. Ishimoto needs to replace the grass in the section of his lawn.

The grass section can be broken into 2 rectangles.

First rectangle: Base = 7 feet and Height = 3 feet.

Second rectangle: Base = 2 feet and Height = 7 feet.

Compute the area of both the rectangles as follows:

\text{Area}_{1}=\text{height}_{1}\times \text{base}_{1}\\=3\times 7\\=21               \text{Area}_{2}=\text{height}_{2}\times \text{base}_{2}\\=7\times 2\\=14

Now the cost of the new grass is $0.40 per square foot.

Compute the cost of replacing the grass in the first rectangular section as follows:

\text{Cost of new grass for section 1}=\text{Area}_{1} \times\$0.40\\

                                                =21\times \$0.40\\=\$8.40

Compute the cost of replacing the grass in the second rectangular section as follows:

\text{Cost of new grass for section 2}=\text{Area}_{2} \times\$0.40\\

                                                =14\times \$0.40\\=\$5.60

The total cost of replacing the grass is:

\text{Total cost}=\text{Cost of new grass for section 1}+\text{Cost of new grass for section 2}

                =\$8.40+\$5.60\\=\$14.00

Thus, the replacing the grass will cost  Mr. Ishimoto $14.00.

3 0
3 years ago
Read 2 more answers
Estimate 4.8 x 4.15.
Nonamiya [84]

Answer:

19.92

Step-by-step explanation:

4.8 x 4.15

8 0
3 years ago
Read 2 more answers
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