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3 years ago

The point (-1,10) lies in which quadrant

Mathematics

2 answers:

matrenka [14]3 years ago

7 0

Answer:

the second quadrant.

Step-by-step explanation:

beks73 [17]3 years ago

7 0

Answer:

Look up a grid and find out. If you don’t know how to number them search that up too and tell you teacher he or she or they are failing you

Step-by-step explanation:

Ahah lol

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A team is excavating an archeological site. The original plan was to excavate a rectangular area 35 ft long

nikitadnepr [17]

Answer:

Part 1) The length of the new rectangle is $87.5\ ft$

Part 2) The area of the new rectangle is $4,375\ ft^{2}$

Step-by-step explanation:

we know that

If two rectangles are similar, then the ratio of its corresponding sides is proportional

step 1

Find the length of the new rectangle

Let

L-----> the length of the new rectangle

$\frac{50}{20}=\frac{L}{35}\\ \\ L=50*35/20\\ \\L=87.5\ ft$

step 2

Find the area of the new rectangle

we know that

The area of the rectangle is

$A=LW$

we have

$L=87.5\ ft$

$W=50\ ft$

substitute

$A=(87.5)(50)=4,375\ ft^{2}$

3 0

3 years ago

Plz help it’s due today

lina2011 [118]

Answer:

From left to right:

1/8

5/8

1-3/16

1-7/8

2-1/2

3-1/8

4-3/8

5-3/8

5-7/8

8 0

3 years ago

Why is -a² is always negative (a ≠ 0) and why is (-a)² is always positive?

hjlf

$-a^2=(-1)\cdot a\cdot a$

Regardless of the sign of $a$ , we have $a\cdot a=a^2\ge0$ (never negative). But multiplying by -1 makes it negative.

On the other hand,

$(-a)^2=((-1)\cdot a)^2=(-1)^2\cdot a^2=1\cdot a^2=a^2$

which can never be negative for real $a$ .

6 0

2 years ago

I need help 3rd try on Ttm lesson

Natasha2012 [34]

The answer is 2900mg because you have to divide the two numders

5 0

3 years ago

How do you do algebra

grin007 [14]

Its not that hard... whats the question

4 0

3 years ago