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vlada-n [284]
3 years ago
9

PLEASE HELP I WILL MARK BRAINLIEST HAVE A GREAT DAY:)!!

Mathematics
2 answers:
Anna71 [15]3 years ago
8 0

\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}

Ur answer is :-

F. 6 \div 5

faltersainse [42]3 years ago
7 0

Answer:

F) 6/5

Step-by-step explanation:

6 divided by 5 = 6/5

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Match each function formula with the corresponding transformation of the parent function y = 3x
kodGreya [7K]

Answer:

1. y = -3^ x Translated up by 1 unit 2.

2.y = 3^ -x Reflected over the y-axis 3.

3.y = 3 ^x - 2 Translated right by 2 units 4.

4. y = 3 ^x + 1 Translated down by 2 units 5.

5. y = 3^ x + 1 Translated left by 1 unit 6.

6. y = 3 ^x - 2 Reflected over the x-axis

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Prove the divisibility:<br><br>45^45·15^15 by 75^30
garri49 [273]

Answer:

3^{75}.

Step-by-step explanation:

We have been an division problem: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(9*5)^{45}=9^{45}*5^{45}

15^{15}=(3*5)^{15}=3^{15}*5^{15}

75^{30}=(15*5)^{30}=15^{30}*5^{30}

Substituting these values in our division problem we will get,

\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}

\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}

\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}

\frac{3^{105}*5^{60}}{3^{30}*5^{60}}

\frac{3^{105}}{3^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{105}}{3^{30}}=3^{105-30}

3^{105-30}=3^{75}

Therefore, our resulting quotient will be 3^{75}.

7 0
3 years ago
What word means if you have spent my money that you earned
djverab [1.8K]

mad money petty cash pin cash pocket money and small change

3 0
3 years ago
Helpppp me please!! I dont understand.
Andrei [34K]

Answer:

A) mPQ = 71º

B) mSR = 161º

C) mQRT = 199ª

D) mPSR = 270º

E) mPS = 109º

Step-by-step explanation:

We know that mST is 19º and QR is also 19º because they're opposite angles. We also know that angle PUR is 90º.

If we subtract 19º from 90º we get 71º for mPQ.

We also know that TR is a 180º angle. Using this if we take 19º from 180º we're left with 161º for mSR.

Using the 180º from angle TR, as well as the 19º from mQR we know that mQRT has to be 199º.

A circle is 360º and a right angle is 90º. That means that mPSR is 270º.

Knowing that TR is 180º and that PR is 90º, PTº must be supplementary making it also 90º. Adding the 19º from ST to the 90º from TP we know that PS is 109º

4 0
3 years ago
Can anybody plzz helpme understand what domain ,funtions and range are?
ahrayia [7]
The domain is all input values(otherwise known as all x-values on the x-axis) and the range is all possible output values( y-values, as shown on the y-axis). Functions are expressions involving 1 or more variables, in a function x-values are only allowed 1 y-value or else it isn’t considered a function.

Hope this helps!
7 0
3 years ago
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