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sweet-ann [11.9K]
3 years ago
10

Find the volume of the conical paper cup.​

Mathematics
2 answers:
Tanya [424]3 years ago
3 0

Answer:

i think it is A sorry if I am worng

vovangra [49]3 years ago
3 0

Answer:

for those who have it as 3 and 8 instead of 7...the answer is 21

Step-by-step explanation:

^_^

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A coffee company ground up 547,736 coffee beans and distributed it evenly into 560 containers. How many coffee beans are in each
weeeeeb [17]
It is 978.1 per container I’m sure
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The slope is 3/4 and they y-intercept is (0, 4​
Paha777 [63]

Answer:

eqn of line

3x-4y=-16

Step-by-step explanation:

6 0
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Factor completely<br> 374 +48r2
irakobra [83]

Answer:

2(187 + 241r)

Step-by-step explanation:

3 0
3 years ago
Each week, mr. jones goes to the grocery store. mr.jones estimates that he will spend $120 when he goes to the grocery store thi
Aliun [14]
Estimated amount that Mr. Jones thought would be spending each week for grocery = $120
Amount actually spent by Mr.Jones in the grocery store = $94
Error in calculation of the amount of spending = (120 - 94) dollars
                                                                           = $26
Percentage error in calculation = (26/120) * 100
                                                   = (13/6) * 10
                                                   = 130/6
                                                   = 21.666 percent
                                                   = 21.67 percent
So there is 21.67% error in the calculation of Mr. Jones. I hope you got the answer you were looking for.

8 0
3 years ago
Factor completely.<br> 150m^2nz+20mn^2c-120m^2nc-25mn^2z
Anika [276]

Answer:

The factor form is:

5mn\left(6m-n\right)\left(5z-4c\right)

Step-by-step explanation:

Here we have to find the factor of the expression:

150m^2nz+20mn^2c-120m^2nc-25mn^2z

So we need to take out the common terms, as we do for finding the greatest common factors.

Now the expression that is given can be re-written as:

150m^2nz+20mn^2c-120m^2nc-25mn^2z\\=150mmnz+20mnnc-120mmnc-25mnnz\\=30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz

Next, we will find the common terms, as follows;

30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz\\=5nm\left(30mz+4nc-24mc-5nz\right)\\

Now  we will factorise the expression:

\left(30mz+4nc-24mc-5nz\right)\\

as follows;

\left(30mz+4nc-24mc-5nz\right)\\=6m\left(5z-4c\right)+n\left(4c-5z\right)\\=\left(-4c+5z\right)\left(6m-n\right)\\

So the final factor form is:

150m^2nz+20mn^2c-120m^2nc-25mn^2z=5mn\left(6m-n\right)\left(5z-4c\right)

8 0
3 years ago
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