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3 years ago

For the following geometric sequence find the recursive formula and the 6th term in the sequence. {12, 8, 4, ...}

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

6 0

It's the arithmetic sequence not geometric sequence.

$\left\{\begin{array}{ccc}a_1=12\\a_n=a_{n-1}-4\end{array}\right$

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Write the equations of three distinct lines that have the same y-intercept,-1.

guajiro [1.7K]

Three possible answers are:
y = 2x-1
y = 5x-1
y = -3x-1

All of them have the same y intercept of -1. The slopes are the only thing that differ.

Any linear equation can be written in the form y = mx+b where
m = slope
b = y intercept

7 0

4 years ago

Find The difference 25(d−10)−23(d+6) is

Vesna [10]

Answer:

2d-388 or 2(d-194)

Step-by-step explanation:

25(d-10)-23(d+6)

25d-250-23d-138

25d-23d-250-138

2d-250-138

2d-388

factor out or simplify,

you get 2(d-194)

8 0

3 years ago

Read 2 more answers

Did i get this right? if not could you tell me what it is.

barxatty [35]

Let’s simply step-by-step.
-9+1/4x-6-1/8x
=-9+1/4x+-6+-1/8 x
COMBINE LIKE TERMS:
=-9+1/4 x + -6 + -1/8 x
=(1/4 x + -1/8 x) + (-9+-6)
Answer
=1/8x -15

5 0

3 years ago

Randy and Susie Moser are newlyweds. Randy drives their car to his job, twenty-seven miles away from home, each day. If Randy an

Andrews [41]

The answer is $834.10

3 0

3 years ago

Read 2 more answers

Zaid has a peculiar pair of four-sided dice. When he rolls the dice, the probability of any particular outcome is proportional t

Elden [556K]

Answer: a) $\bold{\dfrac{3}{16}}$ b) $\bold{\dfrac{1}{36}}$

<u>Step-by-step explanation:</u>

a) In order to get an even number, you have the 3 different scenarios:

1) Even, Even, Even, Even $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

2) Even, Even, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

3) Odd, Odd, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

<em>Order doesn't matter</em>

Add them up to get your answer: $\dfrac{1}{16}+\dfrac{1}{16}+\dfrac{1}{16}\quad =\large\boxed{\dfrac{3}{16}}$

b) If one die is a 2 and another is a 3 and the other two dice can be any number, then you have 1 possibility for a 2, 1 possibility for a 3, and 6 possibilities for each of the other two dice.

$\dfrac{1\times 1\times 6\times 6}{6^4}\quad =\dfrac{1}{6^2}\quad =\large\boxed{\dfrac{1}{36}}$

3 0

3 years ago