For the following geometric sequence find the recursive formula and the 6th term in the sequence. {12, 8, 4, ...}
1 answer:
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Answer:
y = 2(x - 2)² + 3 vertex form
y = 2x² - 8x + 11 standard form
Step-by-step explanation:
Vertex form
y = a(x - h)² + k
(h, k) = (2, 3)
y = a(x - 2)² + 3
To find "a" plug in the y-intercept (0, 11)
11 = a(-2)² + 3
11 = 4a + 3
Subtract 3 from both sides
8 = 4a
a = 2
y = 2(x - 2)² + 3
Expand
y = 2(x² - 4x + 4) + 3
y = 2x² - 8x + 11
Part A:
Look at the image attached to my answer for the graph of the inequalities.
There are two different lines provided, one with a more negative slope than the other. The shaded area between them represents the solution set.
The green line is 2x+y≤8, the blue line is x+y≥4
Part B:
To test if (8, 10) is included, substitute x = 8 and y = 10 into both inequalities. If it doesn't satisfy one of them, then it isn't included in the solution area.
2(8) + 10 ≤ 8
16 + 10 ≤ 8
26 ≤ 8... 26 is NOT less then or equal to 8
Thus, (8, 10) cannot be a solution since the inequality is not true.
Part C:
I'm going to choose a random point from the graph, (2, 3). For your answer, any point in the shaded region where both x and y is positive will work.
The point (2, 3) means that Sarah can buy 2 cupcakes and 3 pieces of fudge to get at least 4 pastries for her siblings while staying within her 8 dollar budget.
Let me know if you need any clarifications. Happy Studying~
