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Vilka [71]
3 years ago
10

Please tell me the final answer and process

Mathematics
1 answer:
Vladimir [108]3 years ago
5 0
I would say 20 because if you add the 10 with 10 the other shaded area so that is why i say 20

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If there is 1/6 of a cake and Mitchell only wants 3/12 of it. how much of the cake does he want?
kherson [118]

he wants 1/24 of the cake

8 0
3 years ago
Read 2 more answers
2.the solution set of x +y =5 and x-y =3
Nataliya [291]

Answer:

Check the solution below

Step-by-step explanation:

2) Given the equation

x +y =5... 1 and

x-y =3 ... 2

Add both equations

x+x = 5+3

2x = 8

x = 8/2

x = 4

Substitute x = 4 into 1:

From 1: x+y = 5

4+y= 5

y = 5-4

y = 1

3) Given

x+3y =15 ... 1

2x+7y=19 .... 2

From 2: x = 15-3y

Substitute into 2

2(15-3y)+7y = 19

30-6y+7y = 19

30+y = 19

y = 19-30

y = -11

Substitute y=-11 into x = 15-3y

x =15-3(-11)

x = 15+33

x = 48

The solution set is (48, -11)

4) given

x/2 +y/3 =0 and x+2y=1

From 1

(3x+2y)/6 = 0

3x+2y = 0.. 3

x+2y= 1... 4

From 4: x = 1-2y

Substutute

3(1-2y) +2y = 0

3-6y+2y = 0

3 -4y = 0

4y = 3

y = 3/4

Since x = 1-2y

x = 1-2(3/4)

x = 1-3/2

x= -1/2

The solution set is (-1/2, 3/4)

5) Given

5.x=1/2 and y =x +1 then solution is

We already know the vkue of x

Get y

y= x+1

y = 1/2 + 1

y = 3/2

Hence the solution set is (1/2, 3/2)

6) Given

3x +y =5 and x -3y =5

From 3; x = 5+3y

Substitute into 1;

3(5+3y)+y = 5

15+9y+y = 5

10y = 5-15

10y =-10

y = -1

Get x;

x = 5+3y

x = 5+3(-1)

x = 5-3

x = 2

Hence two solution set is (2,-1)

6 0
3 years ago
Can someone please help me?
melamori03 [73]

Answer:

Answer is B

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Given an acceleration vector, initial velocity u0,v0,w0 , and initial position x0,y0,z0 , find the velocity and position vectors
dsp73

Answer:

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

Step-by-step explanation:

given that acceleration vector is a funciton of time and at time t

a(t) = (5,5t, 8t)

v(t) can be obtained by integrating a(t)

v(t) = (5t, 5t^2/2, 4t^2)+(u_0,v_0,w_0)\\=(5t+15, 5t^2/2, 4t^2)

Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.

The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)

Position vector can be obtained by integrating v(t)

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

5 0
3 years ago
CAN ANYBODY HELP ME WITH THIS JUST WITH 7 TO 12 PLEASE IT IS FOR AN GRADE!!
mafiozo [28]

Answer: I think there is a mistake for the first one because I did the math and I got 200 added but then there are more answers to this one, I added all the others by 200 and got the next number but then when I got to 6,300 I can't get the 6,700. I get something else, I add 6,000 with 200, and then I get 6,200 instead of getting 6,300. Then I added that 6,200 and 200 and got 6,400. I am confused with the second one, can you please help me understand that one. The third one is also confusing, The one is 12 nuggets eaten per minute. The fifth I am not sure if that is a solvable question, The sixth one I am not sure but I think that it is 0.066667. The seventh one doesn't even make any sense to me.

Explanation: I am sorry this was so long, I was trying to make sense of these questions. Also if this is ALL wrong sorry for even trying.

7 0
3 years ago
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