Use the law of cosines:
c² = 8² + 11² - 2•8•11 cos(37°)
c² ≈ 44.4402
c ≈ 6.66634
Answer:
The distance covered is 113.75 m
Step-by-step explanation:
As per the question:
The initial velocity of the train, v = 20 m/s
The final velocity of the train, v' = 6 m/s
Uniform deceleration, a = 1.6
Or uniform acceleration, a = - 1.6
<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>
Now, to find the distance covered, s:
Using the eqn of Kinemetics:




Answer:

Step-by-step explanation:
12+11x=17x11x+12=17x
(both sides of the equation)
11x+12−17x=17x−17x
(Subtract 17x from both sides)
−6x+12=0−6x+12−12=0−12
(Subtract 12 from both sides)
−6x=−12−6x−6=−12−6
(Divide both sides by -6)
x=2
Check answers. (Plug them in to make sure they work.)
x=2
(Works in original equation)