refection and translation i think
hdjdjsjsj I hope I got it right
I'm not sure if its a dilation if its getting smaller not bigger
Answer:
-10
-5
5
Step-by-step explanation:
From the answers given, you probably mean f(x) = x^3 + 10x2 – 25x – 250
The Remainder Theorem is going to take a bit to solve.
You have to try the factors of 250. One way to make your life a lot easier is to graph the equation. That will give you the roots.
The graph appears below. Since the y intercept is -250 the graph goes down quite a bit and if you show the y intercept then it will not be easy to see the roots.
However just to get the roots, the graph shows that
x = -10
x = - 5
x = 5
The last answer is the right one. To use the remainder theorem, you could show none of the answers will give 0s except the last one. For example, the second one will give
f((10) = 10^3 + 10*10^2 - 25*10 - 250
f(10) = 1000 + 1000 - 250 - 250
f(10) = 2000 - 500
f(10) = 1500 which is not 0.
==================
f(1) = (1)^3 + 10*(1)^2 - 25(1) - 250
f(1) = 1 + 10 - 25 - 250
f(1) = -264 which again is not zero
Answer:
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Step-by-step explanation:
1 n=0
1 1 n=1
1 2 1 n=2
1 3 3 1 n=3
1 4 6 4 1 n=4
1 5 10 10 5 1 n=5
1 6 15 20 15 6 1 n=6
This is where n is the exponent in
.

Now we want to expand:
or we we can rewrite as
.
Let's replace
with
and
with
in the expansion:



Let's simplify a bit:


Add 4 to both sides to isolate the variable (-4+4=0) (2x+0=2x) (0+4=4) which leaves you with 2x=4 divide both sides by 2 to get rid of the number in front of the variable to get x by itself (2x/2=x) (4/2=2) therefore you’re left with x=2 (lo siento yo no hablo español la respuesta es x=2)
<u>Answer:</u>
The total number of whole cups that we can fit in the dispenser is 25
<u>Solution:</u>
It is given that the height of each cup is 20 cm.
But when we stack them one on top of the other, they only add a height of 0.8 to the stack.
The stack of cups has to be put in a dispenser of height 30 cm.
So we need o find out how many cups can fit in the dispenser.
Since the first cup is 20 cm high, the height cannot be reduced. So the space to fit in the remaining cups in the stack is only 30-20 cm as that’s the remaining space in the dispenser
So,
30 - 20 = 10 cm
To stack the other cups we have 10 cm of height remaining
As we know that addition of each adds 0.8 cm to the stack, the total number of cups that can be fit in the dispenser can be calculated by the following equation. Let the number of cups other than the first cup be denoted by ‘x’.
10 + 0.8x = 30
0.8x = 20
x = 25
The total number of cups that we can fit in dispenser is 25