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shusha [124]
3 years ago
14

Please answer question 44

Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0

The sum will be prime if its 2, 3, 5, 7, 9, 11, or 13

0+2=2

1+2=3

5+2=7

9+2=11

0+3=3

1+4=5

9+4=13

0+7=7

That's 8 combinations, and there 4*4=16 total.

8/16 = 1/2.

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What number gives a result of −5 when 9 is subtracted from the quotient of the number and 6?
My name is Ann [436]

Answer:

25

Step-by-step explanation:

If it gives a result of -4 then our equation will have .... = -4

 

If we subtract 9 from the quotient of a number and 5 we have  x/5 - 9

 

Our equation is:

 

x/5 - 9 = -4     add 9 to both sides

x/5 = -4 + 9

x/5 = 5           multiply both sides by 5

x = 5(5)

x = 25

Check:  25/5 - 9 = 5-9 = -4

           Answer checks as correct from information given

 

8 0
2 years ago
10)
Hitman42 [59]
I think the answer is B
4 0
3 years ago
Can anyone help me about question 2
madreJ [45]

9514 1404 393

Answer:

  3(4/3)^2543

Step-by-step explanation:

Using logarithms base 2, we have ...

  (a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

  \log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}

and the 2544th term is ...

  \boxed{\log_2{a_{2544}}=3\left(\dfrac{4}{3}\right)^{2543}}

8 0
2 years ago
11=u/28 what does U =
ra1l [238]

U=308

11=308/28

it right trust me

8 0
1 year ago
Read 2 more answers
If y is 22.6 and c is 28.2, find b, rounded to the nearest tenth.
Nat2105 [25]
Can u send the question to be more clear
6 0
3 years ago
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