Answer:
yes it would change since pop sticks are lighter than blocks are.
Answer:
The answer to your question is a = 16
Step-by-step explanation:
Polynomial
(y - 4) (y² + 4y + 16)
Process
1.- Multiply y by each term of the polynomial
y(y² + 4y + 16) = y³ + 4y² + 16y
2.- Multiply -4 by each term of the polynomial
-4(y² + 4y + 16) = -4y² - 16y - 64
3.- Write both results
y³ + 4y² + 16y - 4y² - 16y - 64
In bold we notice that a = 16
Answer:
2, 19, -3
Step-by-step explanation:
Answer:
050°
Step-by-step explanation:
The bearing of D from C is the angle between the north pole and the line joining C and D when moving in a clockwise direction.
From the diagram, the angle is 050°
25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path. This can be obtained by considering this as a right angled triangle.
<h3>How fast is the tip of his shadow moving?</h3>
Let x be the length between man and the pole, y be the distance between the tip of the shadow and the pole.
Then y - x will be the length between the man and the tip of the shadow.
Since two triangles are similar, we can write

⇒15(y-x) = 6y
15 y - 15 x = 6y
9y = 15x
y = 15/9 x
y = 5/3 x
Differentiate both sides
dy/dt = 5/3 dx/dt
dy/dt is the speed of the tip of the shadow, dx/dt is the speed of the man.
Given that dx/dt = 5 ft/s
Thus dy/dt = (5/3)×5 ft/s
dy/dt = 25/3 ft/s
Hence 25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path.
Learn more about similar triangles here:
brainly.com/question/8691470
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