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evablogger [386]
2 years ago
7

A flow meter is attached in a hydraulic line that measures 18 gal/min. The line has an inside diameter of 1.0 in. What is the fl

ow velocity measured as in/min at the meter? (1 gallon = 231 in3)
in/min
Mathematics
1 answer:
snow_tiger [21]2 years ago
5 0

The flow velocity measured as in/min at the meter is 5924.13 in/min

<h3 /><h3>Volumetric flow rate</h3>

We know that the volume flow rate Q = Av where

  • A = cross-sectional area of pipe and
  • v = flow velocity

Now, Q = 18 gal/min

Converting this to in³/min, we have

Q = 18 gal/min = 18 × 1 gal/min = 18 × 231 in³/min = 4158 in³/min

A = πd²/4 where d = diameter of pipe = 1.0 in.

<h3 /><h3>Flow velocity, v</h3>

Since Q = Av, making v subject of the formula, we have

v = Q/A

v = 4Q/πd²

Substituting the values of the variables into the equation, we have

v = 4Q/πd²

v = 4 × 4158 in³/min ÷ π × (1.0 in)²

v = 16632 in/min ÷ π

v = 5924.13 in/min

So, the flow velocity measured as in/min at the meter is 5924.13 in/min

Learn more about flow velocity here:

brainly.com/question/15648466

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2 years ago
What is the equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4)?
Nastasia [14]

Answer:

The equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5

Option A is correct.

Step-by-step explanation:

We need to find equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4)

We need a line parallel to x=-2 or x+2=0 it should be of form x+k=0

We need to find k, by putting value of x=-5 as given in question the point(-5,4)

-5+k=0

k=5

So, the equation of line will be found by putting k=5:

x+k=0

x+5=0

x=-5

So, the equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5

Option A is correct.

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3 years ago
Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

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Answer:

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