Answer:
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given mean of the population = 500 </em>
<em>Given standard deviation of the Population = 75</em>
Let 'X' be the variable in normal distribution

<em>Given X = $410</em>
<em></em>
<em></em>
<u><em>Step(ii):-</em></u>
The probability that a family spends less than $410 per month
P( X < 410) = P( Z < - 1.2 )
= 0.5 - A( -1.2)
= 0.5 - A(1.2)
= 0.5 - 0.3849 ( ∵from normal table)
= 0.1151
<u>Final answer:-</u>
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Answer:
-a - 4
Step-by-step explanation:
3(a-2)+4(3-a)-10
3a - 6 + 12 - 4a - 10
-a - 4
The answer would be $175
Multiply the most by the number of tickets
Answer:
C. October
Explanation:
Because all the other month only have 2-3 units between their high and low October has four units between its high and low