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2 years ago

Complete the equation of the line whose slope is -2 and y-intercept is (0,-8) y=

Mathematics

2 answers:

Alexandra [31]2 years ago

7 0

Answer:

y = -2x - 8

Step-by-step explanation:

We want to find the slope-intercept form of this equation. Slope-intercept form is denoted by: y = mx + b, where m is the slope and b is the y-intercept.

We already know that the slope is -2, so that means m = -2.

We also know the y-intercept (or the point where the line crosses the y-axis) is (0, -8), which means b = -8.

Thus, our equation is: y = -2x - 8.

<em>~ an aesthetics lover</em>

Flauer [41]2 years ago

7 0

y=-2x-8 this should be right i had this same problem before :)

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Based on a survey of U.S. residents completed in 2014, ___________ percent of respondents agreed that global warming is occurrin

Daniel [21]

Using the percentage concept, supposing 520 out of 1000 respondents believe in global warming, 52% of respondents agreed that global warming is occurring.

<h3>What is a percentage?</h3>

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

$P = \frac{a}{b} \times 100\%$

In this problem, we suppose that 520 out of 1000 respondents believe in global warming, hence a = 520, b = 1000, and the percentage is of:

$P = \frac{520}{1000} \times 100\% = 52\%$

More can be learned about the percentage concept at brainly.com/question/10491646

3 0

1 year ago

find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0

Citrus2011 [14]

Answer:

Radius: $r =\frac{\sqrt {21}}{6}$

$Center = (-\frac{3}{2}, -\frac{2}{3})$

Step-by-step explanation:

Given

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Solving (a): The radius of the circle

First, we express the equation as:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

So, we have:

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Divide through by 9

$x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0$

Rewrite as:

$x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}$

Group the expression into 2

$[x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}$

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

Next, we complete the square on each group.

For $[x^2 + 3x]$

1: Divide the $coefficient\ of\ x\ by\ 2$

2: Take the $square\ of\ the\ division$

3: Add this $square\ to\ both\ sides\ of\ the\ equation.$

So, we have:

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

$[x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Factorize

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Apply the same to y

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}$

Add the fractions

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}$

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

By comparison:

$r^2 =\frac{7}{12}$

Take square roots of both sides

$r =\sqrt{\frac{7}{12}}$

Split

$r =\frac{\sqrt 7}{\sqrt 12}$

Rationalize

$r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}$

$r =\frac{\sqrt {84}}{12}$

$r =\frac{\sqrt {4*21}}{12}$

$r =\frac{2\sqrt {21}}{12}$

$r =\frac{\sqrt {21}}{6}$

Solving (b): The center

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

From:

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

$-h = \frac{3}{2}$ and $-k = \frac{2}{3}$

Solve for h and k

$h = -\frac{3}{2}$ and $k = -\frac{2}{3}$

Hence, the center is:

$Center = (-\frac{3}{2}, -\frac{2}{3})$

6 0

2 years ago

Tam multiplied 2.13 and 4.62, as shown. But he forgot to put a decimal point in his

yuradex [85]

The decimal gives after the 9. There are four places behind the decimal between the two numbers being multiplied so there have to be 4 places behind the decimal in your answer.

8 0

2 years ago

Read 2 more answers

Find the integers of 181

GalinKa [24]

If you mean its factors, it's a prime number, so the only integers that it factors into are -1, 1, -181, and itself.

6 0

2 years ago

What other point will appear on the line representing this proportional relationship where the constant of proportionality is 2?

Bumek [7]

Answer:

Step-by-step explanation:

The equation of proportionality is

y = kx ← k is the constant of proportionality

Here k = 2 , then

y = 2x

This means that the y- coordinate is twice the x- coordinate

The only point where this is true is the point

(2, 4 ) → B

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2 years ago