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KatRina [158]
3 years ago
13

A party rental company has chairs and tables for rent. The total cost to rent 8 chairs and 3 tables is $38 . The total cost to r

ent 2 chairs and 5 tables is $35 . What is the cost to rent each chair and each table?
Mathematics
1 answer:
faltersainse [42]3 years ago
5 0
Each table is $6
Each chair costs $2.50

if correct please give<span> brainliest

Thankyou :)</span>
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A rectangular garden has a walkway around it. The area of the garden is 6(6.5x + 2.5). The combined area of the garden and the w
Rasek [7]

According to the information given in the exercise, the following expression represents the area of the rectangular garden:

6\mleft(6.5x+2.5\mright)

And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

6.5\mleft(8x+6\mright)

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.

Knowing the above, you can set up the following equation:

6(6.5x+2.5)+A=6.5(8x+6)

Where "A" is the area of the walkway around the rectangular garden.

Solving for "A", you get the following expression:

\begin{gathered} A=6.5(8x+6)-6(6.5x+2.5) \\ A=52x+39-39x-15 \\ A=13x+24 \end{gathered}

The answer is:

13x+24

7 0
1 year ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis
MArishka [77]
If Car A's speed is x, then Car B's speed is x-22. Using the formula, we get that the distance is the same in both, so 4*(x-22)=D and 2.4*x=D due to that we plug 2.4 and 4 in for T and x-22 and x for R. Since they both equal D, we can write it as 2.4*x=4*(x-22). Using the distributive property, we get 4*(x-22)=4x-88=2.4*x. Subtracting 2.4*x from both sides as well as adding 88, we get 1.6*x=88. Dividing both sides by 1.6, we get 88/1.6=55= x=Car A's speed
3 0
3 years ago
Read 2 more answers
Need help on this, I never learned how to do this yet and it’s on homework
Wewaii [24]

For a function f(x), its average rate of change on an interval [a, b] is given by what's called the "difference quotient",

\dfrac{f(b)-f(a)}{b-a}

and is basically the ratio of the difference in values of f(x) at the endpoints to the difference in the endpoints themselves.

I assume the 6 intervals below each table correspond to each table immediately above them.

From the first table, we get the following average rates of change (after arranging the intervals from left to right):

• [-3, -2] : (f(-2) - f(-3)) / (-2 - (-3)) = (7 - 12)/1 = -5

• [-2, -1] : (f(-1) - f(-2)) / (-1 - (-2)) = (4 - 7)/1 = -3

• [-1, 0] : (f(0) - f(-1)) / (0 - (-1)) = (3 - 4)/1 = -1

• [0, 1] : (f(1) - f(0)) / (1 - 0) = (4 - 3)/1 = 1

• [1, 2] : (f(2) - f(1)) / (2 - 1) = (7 - 4)/1 = 3

• [2, 3] : (f(3) - f(2)) / (3 - 2) = (12 - 7)/1 = 5

Just do the same for the other two tables. Note that each listed interval has length 1, so practically, each average rate of change over [a, b] is exactly f(b) - f(a).

For parts (c) and (d):

• (c) You'll notice that each of the average rates of change are odd numbers …

• (d) … but they're not necessarily all the same size, and they follow slightly different patterns.

5 0
2 years ago
MAY SOMEBODY HELP ME THANKS!
n200080 [17]

Answer:

i think it’s A. it only makes sense

5 0
3 years ago
PLEASE HELP THIS IS PASS OR FAIL
tigry1 [53]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
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