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goldfiish [28.3K]
3 years ago
13

Math question down below

Mathematics
1 answer:
NARA [144]3 years ago
6 0
B is correct because looking at the chart there is less sold at South and D because there were more bags sold at west
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Can someone help me for this question please? Why I got wrong answer. ASAP!!!
Snowcat [4.5K]

Answer:

a=8.06

A=29.74

B=60.26

Step-by-step explanation:

This is a right angled triangle and Pythagoras theorem is to be obeyed.

To get c, we follow the Pythagoras rule that says

Hyp² = Opp² + Adj²

c= Hypotenuse

c²= a² + b²

c² = 4² + 7²

c² = 65

c = √65 = 8.06

For angle A,

the opposing side to the angle = a = 4

The adjacent side to the angle = b = 7

Following trigonometry rule.

Tan A = opp/adj

Tan A = 4/7

A = Tan–¹(4/7)

A = 29.74°

For angle B,

Opposing side = 7

Adjacent side = 4

Tan B = 7/4

B = Tan-¹(7/4)

B = 60.26°

5 0
3 years ago
-2b^2-18b^2<br> Help me. Plz
satela [25.4K]

Answer:

{ \tt{ -  {2b}^{2}  - 18 {b}^{2} }} \\ =   -  {20 {b}^{2}}

7 0
3 years ago
Karen runs a print shop that makes posters for large companies. It is a very competitive business. The market price is currently
kumpel [21]
AFC = FC / Quantity printed 

<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>

<span>ATC = TC / Quantity printed </span>

<span>where TC = FC + Variable C * Quantity printed </span>

<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>

<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>

<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
7 0
3 years ago
Please help out it would be great help I need the answer before 8pm
Diano4ka-milaya [45]

A reflection over the y-axis :)

5 0
3 years ago
Read 2 more answers
Find the interval(s) over which the function is decreasing
son4ous [18]

Answer : (0,3) U  (3, ∞)

We need to find  the interval(s) over which the function is decreasing

We look at the intervals of x  where the graph is decreasing

Decreasing interval of the graph is the part where the graph goes down

We look at the part where the graph changes direction

In the middle  inverted U shaped graph , the graph changes direction and start decreasing at x=0

the graph is decreasing till x=3

so first decreasing interval is x=0  to 3. we write it as (0,3)

After x=3 the graph starts decreasing and it goes to infinity

So the second decreasing interval is 3  to infinity . We write it as (3, ∞)

Now combine both intervals by a 'U' union

(0,3) U  (3, ∞)

7 0
3 years ago
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