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____ [38]
3 years ago
6

D/dx (5x4) - (2x³) - (x²)

Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0
\bf y=5x^4-2x^3-x^2\implies \cfrac{dy}{dx}=20x^3-6x^2-2
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If g(x) =5-9x and f(x) = 5+ 3x <br> Find g(2)<br> Find f(g(2))
alekssr [168]

Answer:

Step-by-step explanation:

g(2)= 5-9(2)

= -13

f(g(2))= 5+3(-13)

= -34

5 0
3 years ago
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21 is what percent of 50
Alexxandr [17]
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3 years ago
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Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.
Ann [662]

Given:

Consider the given function is:

f(x)=x^2-8x+13

To find:

The average rate of change of the function over the interval -1\leq x\leq 6.

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}

We have,

f(x)=x^2-8x+13

At x=-1,

f(-1)=(-1)^2-8(-1)+13

f(-1)=1+8+13

f(-1)=22

At x=6,

f(6)=(6)^2-8(6)+13

f(6)=36-48+13

f(6)=1

Now, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is:

m=\dfrac{f(6)-f(-1)}{6-(-1)}

m=\dfrac{1-22}{7}

m=\dfrac{-21}{7}

m=-3

Therefore, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is -3.

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2 years ago
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Answer:

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For 22 hours, he earns 22 times his hourly pay.

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3 years ago
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Answer: no but some people do

Step-by-step explanation:

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