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3 years ago

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Mathematics

1 answer:

Nostrana [21]3 years ago

3 0

Answer:

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Step-by-step explanation:hope i helped

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If cos A = 3 over 11, then which of the following is correct?

ziro4ka [17]

Answer: The answer is (a) sec A = 11 over 3.

Step-by-step explanation: Given that Cosine of an angle 'A' is 3 over 11,

i.e.,

$\cos A=\dfrac{3}{11}.$

And we need to find which one of the given four options is correct.

We have the following relations between cosine, secant and cosecant of an angle from trigonometry.

$\sec A=\dfrac{1}{\cos A}~~\textup{and}~~\csc A=\dfrac{1}{\sqrt{1-\cos^2 A}}.$

Therefore,

$\sec A=\dfrac{11}{3}$

and

$\csc A=\dfrac{1}{\sqrt{1-\frac{9}{121}}}=\dfrac{1}{\sqrt{\frac{112}{121}}}=\dfrac{11}{4\sqrt 7}.$

Thus, the correct option is (a) sec A = 11 over 3.

3 0

3 years ago

Which numbers should be multiplied to obtain 175^2 − 124^2?

Tomtit [17]

Hi There! :)

<span>Which numbers should be multiplied to obtain 175^2 − 124^2?

</span><span>51 and 299</span>

7 0

3 years ago

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A regular hexagon has sides of 3 feet. What is the area of the hexagon?

frosja888 [35]

Answer:

$13.5\sqrt{3}\:\text{ft}^{2}$

Step-by-step explanation:

Given: The side of a regular hexagon is 3 feet.

To find: Area of the hexagon

Solution:

It is given that the side of a regular hexagon is 3 feet.

We know that the area of a regular hexagon whose side is a units is $\frac{3\sqrt{3} }{2} a^{2}$

Here, the side is 3 feet

So, area of the regular hexagon

$=\frac{3\sqrt{3} }{2} \times3^{2}$

$=\frac{3\sqrt{3} }{2} \times9$

$=\frac{27\sqrt{3} }{2}$

$=13.5\sqrt{3}\:\text{ft}^{2}$

Hence, area of the regular hexagon is $13.5\sqrt{3}\:\text{ft}^{2}$

6 0

3 years ago

Can y’all please help?

alex41 [277]

Answer:

Step-by-step explanation:

You subtract 220 - 129 = 91 then divide by 13

4 0

3 years ago

60 - 3d + 20 - 6 = 4d

iragen [17]

60-3d + 20-6 =4d
74-3d =4d
-3d =4d -74
-7d = -74
D=74/7

4 0

2 years ago

Read 2 more answers