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3 years ago

11

Math question down below

2 answers:

kobusy [5.1K]3 years ago

5 0

Converting to improper fractions
27/8 • 13/3
9/8•13
=117/8
=14 5/8

SpyIntel [72]3 years ago

3 0

3 3/8 · 4 1/3

To make this easier to solve, let's change the mixed numbers into improper fractions. This is done by multiplying the denominator (8) by the whole number (3) and then adding that to the numerator (3), keeping the denominator the same. Do the same thing with the second fraction.

27/8 × 13/3
Now you can multiply.
(27 × 13)/(8 × 3)
351/24

Now think of how many times 24 can go into 351. You can find this out by plugging it into a calculator. You should get 14.625. Since we need a whole number though, round down to 14.
14 × 24 = 336
This means that there will be 15 left over.
So far the fraction looks like this:
14 15/24

The last thing you need to do is simplify. A number that can go into both 15 and 24 is 3, so divide them by that.
14 5/8

The answer is
D. 14 5/8

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3 years ago

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2 years ago

What changes would you make in your description of point, line, and plane?

weeeeeb [17]

Answer:

Here's a quick sketch of how to calculate the distance from a point P=(x1,y1,z1)

P

=

(

x

1

,

y

1

,

z

1

)

to a plane determined by normal vector N=(A,B,C)

N

=

(

A

,

B

,

C

)

and point Q=(x0,y0,z0)

Q

=

(

x

0

,

y

0

,

z

0

)

. The equation for the plane determined by N

N

and Q

Q

is A(x−x0)+B(y−y0)+C(z−z0)=0

A

(

x

−

x

0

)

+

B

(

y

−

y

0

)

+

C

(

z

−

z

0

)

=

0

, which we could write as Ax+By+Cz+D=0

A

x

+

B

y

+

C

z

+

D

=

0

, where D=−Ax0−By0−Cz0

D

=

−

A

x

0

−

B

y

0

−

C

z

0

.

This applet demonstrates the setup of the problem and the method we will use to derive a formula for the distance from the plane to the point P

P

.

Step-by-step explanation:

5 0

3 years ago

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFracti

weqwewe [10]

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

$x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

To find the solution of the quadratic equation by using quadratic formula

Find the values of a, b, and c from the quadratic equation
Substitute these values in the quadratic formula
Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ $x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4+\sqrt{16+60}}{-6}$

∴ $x=\frac{4+2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2-\sqrt{19}}{3}$

∵ $x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4-\sqrt{16+60}}{-6}$

∴ $x=\frac{4-2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2+\sqrt{19}}{3}$

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Learn more:

You can learn more about quadratic equation in brainly.com/question/7361044

#LearnwithBrainly

9 0

3 years ago

Read 2 more answers