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Triss [41]
3 years ago
9

Can someone help me on this problem?

Mathematics
2 answers:
gtnhenbr [62]3 years ago
8 0
Answer:
Vertices- 5
Faces- 5
Tanya [424]3 years ago
5 0

Answer:

5vertices

Step-by-step explanation:

the answers is 5,5

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A room measuring 6m x 4m is carpeted leaving space of 25cm all around. Find the area of the carpet.​
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Step-by-step explanation:

Length = 6m

Breadth =4m

Area = length\times breadth\\\\A = 6\times 4\\\\A= 24cm^2

8 0
4 years ago
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Find the next three terms of the sequence 80, –160, 320, –640
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There is an unknown number of people at the beginning of lunch. Then...
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4 0
3 years ago
Which equation represents the statement below?
Sergio [31]

The answer is option A

Step-by-step explanation:

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Hope this helps you

3 0
3 years ago
A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man
Jet001 [13]
A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees 

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
  3 W + 2 M OR (we have found it in c) = 2,520)
  4 W + 1 M OR   ⁸C₄ x ¹⁰C₁   →→→→ =    700
  5 W + 0 M OR   ⁸C₅ x ¹⁰C₀   →→→→  =     56

Total where W>M = 3,276 groups of 5 where women are at least 3


3 0
3 years ago
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