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lawyer [7]
3 years ago
9

If all of the diagonals are drawn from a vertex of a hexagon, how many triangles are formed?

Mathematics
2 answers:
Romashka [77]3 years ago
8 0

Answer:

4

Step-by-step explanation:

Elan Coil [88]3 years ago
5 0
If we consider it as a combination problem, then we could calculate the how many combinations are there if we pick up three nodes out of six nodes, and then we have:
C_{6}^{3}= \frac{6*5*4}{3*2*1}  =20
And the answer should be 20
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2 years ago
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Simplify the expression by combining like terms.
Tju [1.3M]

Answer:

8x + 13

Step-by-step explanation:

"Like terms" means the same kind of algebraic expression...the 6x and the 2x are "like terms" because they both have an x in them. The 9 and the 4 are both constants, which means they are plain numbers. So 6x and 2x is 8x .

9+4 is 13 just like elementary school.

So all together,

6x + 9 + 2x + 4

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4 0
2 years ago
Look At picture! Below!
eimsori [14]

Answer:

The answer is: the second one

Step-by-step explanation:

                                             (2x + 2)/y = 4w + 2

pass y to the right side        2x + 2 = y(4w + 2)

expand                                   2x +2 = 4wy + 2y

pass 2 to the right                2x = 4wy + 2y -2

pass 2 to the right                x = (4wy + 2y - 2)/2

simplify                                  x = 2wy + y - 1 or = 2yw + y -1

8 0
3 years ago
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zvonat [6]
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3 years ago
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Sav [38]

Answer:

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Step-by-step explanation:

plug in

8(6)- (-3)

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51

8 0
3 years ago
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