The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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First replace x and y by 3 and 4.
(3*(x)+1)/(4*(y)^2)
((3*(3))+1)/(4*((4)^2)) = (9+1)/(4*16) = 10/64 = 5/32.
5/32 is your answer.
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I believe it would be 4 1/10 ,4.104, 104/25, 4.74
Answer:
8
Step-by-step explanation:
I got 8 in a short version. The full answer is not complete. It is 8.18812697...
But if you shorten it, 8 is the best estimation.
