<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer:
17
Step-by-step explanation:
(X-4)2+(y+12)2=17^2
radius is square root of 17^2
Answer:
y=-2x^2+10x-12
Step-by-step explanation:
graph is shown in image below
Answer:
6in
Step-by-step explanation:
Using the pythagerous thereom,
10^2 = 8^2 + b^2
b^2 = 10^2-8^2
b^2 = 100-64
b^2 = 36
b = 6
<em>Feel free to mark this as brainliest :D</em>
