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ser-zykov [4K]
3 years ago
7

(5-5)^2 - (6-5)^3 simplify the expression PLEASE HELP

Mathematics
2 answers:
leonid [27]3 years ago
7 0

Answer: 15

Step-by-step explanation:

(5-1)^2 - (6-5)^3

(4)^2 - (1)^3

16-1

=15

Firdavs [7]3 years ago
4 0
Hijvfnbddgyuhfsdvjutsfvjhrdxghtdghjuyffhjjyfcbnjggbh
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On Saturday morning Briana and her friends walked 1.35 miles. What is the distance as a decimal
padilas [110]

Answer:

1.35 miles is the distance walked in decimal form

Step-by-step explanation:

1 (decimal) 35

3 0
2 years ago
What is 92.9 rounded to the nersst whole number
sammy [17]
The nearest whole number would be 93 because you round up if the decimal place is greater than 5 and down if it's less.
5 0
3 years ago
Whatdkdjfdjjfksakknshaja
trapecia [35]
i think you have to multiply those. thats it
8 0
3 years ago
g Two teams compete in the NBA (National Basketball Associa- tion) championshipseries. The team who wins four games out of seven
Firlakuza [10]

Answer: The required probability is 0.32.

Step-by-step explanation:

Since we have given that

Probability of winning team A over B = 0.7

Probability of losing team A over B = 0.3

Number of matches = 7"

So, using the "Binomial distribution" :

We get that

P(X=5)=^7C_5(0.7)^5(0.3)^2=0.32

Hence, the required probability is 0.32.

4 0
3 years ago
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
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