Question

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0?

Answer 1

Solving for x
6x^2 + 23x - 4 = 0
Factoring
(6x - 1)(x + 4) = 0
6x - 1 = 0 or x+ 4 = 0

X = 1/6 or x = -4

Answer 2

Answer:

B.) x = –4 or x = 1/6 .

Step-by-step explanation:

Given  : g(x) = 6x² + 23x – 4.  

To find : Solve.

Solution : We have given that

g(x) = 6x² + 23x – 4.  

If g(x) = 0

6x² + 23x – 4 = 0 .

On factoring

6x² + 24x - 1x – 4 = 0

Taking common 6x from first two terms and -1 from last two terms.

6x ( x + 4 ) -1 (x + 4) = 0.

On grouping

(6x -1) ( x +4) = 0

For 6x -1 = 0

6x = 1

on dividing by 6

x = 1/6.

For x +4 = 0

On subtracting 4 from both sides

x = -4.

Therefore, B.) x = –4 or x = 1/6 .