X^2 +3x-4=0
(X+4)(x-1)=0 so x = -4 and x=1 are solutions
Remark
There is no short way to do this problem and no obvious way to get the answer other that to solve each part.
Solve
A
Multiply by 2
x + 1.6 = 2(x + 0.1) Remove the brackets
x + 1.6 = 2x + 0.1*2
x + 1.6 = 2x + 0.2 Subtract x from both sides
1.6 = x + 0.2 Subtract 0.2 from both sides
1.6 - 0.2 = x
1.4 = x
Circle A
B
Subtract 2x from both sides.
3x - 2x = 1.4
Circle B
C
Remove the brackets.
4x + 6 = 2x - 6 Add 6 to both sides
4x + 12 = 2x Subtract 4x from both sides.
12 = -2x Divide by - 2
12/-2 = x
x = - 6 Don't circle C
D
I'm going to be very scant in my solution of this. You can fill in the steps.
3x = 4.2
x = 4.2/3
x = 1.4
Circle D
Answer:
B. 3x+5−4x=−(x+8)
Explanation:
3x+5−4x=−(x+8)
Step 1: Simplify both sides of the equation.
3x+5−4x=−(x+8)
3x+5+−4x=−x+−8
(3x+−4x)+(5)=−x−8
−x+5=−x−8
−x+5=−x−8
Step 2: Add x to both sides.
−x+5+x=−x−8+x
5=−8
Step 3: Subtract 5 from both sides.
5−5=−8−5
0=−13
So, there is no solution
Hope this Helps!
Step-by-step explanation:

Answer:
Z = 6
Step-by-step explanation:
Z/12 = Cos(60°)
Z/12 = 1/2